Subtract 968 minus 89: Vertical Format Solution

Question

amp;968amp;amp;  89amp;776amp; \begin{aligned} &968 \\ -& \\ &~~89 \\ &\underline{\phantom{776}} & \\ \end{aligned}

Video Solution

Solution Steps

00:00 Solve
00:03 Each time we consider a shortage of 2 digits, and then we place
00:05 8 is less than 9
00:12 Therefore we subtract 1 from the tens and add this amount to the ones
00:17 Meaning now instead of 8 we will have 18
00:22 We subtract the ones from the ones plus ten
00:27 We place in the ones
00:31 5 is less than 8
00:37 Therefore we subtract 1 from the hundreds and add this amount to the tens
00:41 Meaning now instead of 5 we will have 15
00:46 We subtract the tens from the tens plus ten
00:52 We place in the tens
00:56 We place 0 in the missing digits
01:00 Subtract hundreds from hundreds, and place in hundreds
01:03 And this is the solution to the question

Step-by-Step Solution

To solve the problem 96889968 - 89 using vertical subtraction, follow these steps:

  • Align the numbers vertically by place value:

 amp;9amp;6amp;8amp; amp;8amp;9 \begin{array}{c} ~ & 9 & 6 & 8 \\ - & ~ & 8 & 9 \\ \hline \end{array}

  • Subtract the rightmost column (units):
    Since 898 - 9 is not possible directly, we borrow 1 from the tens column.

  • After borrowing, the units column becomes 189=918 - 9 = 9.

 amp;9amp;6 5amp;18amp; amp;8  amp;9 amp; amp; amp;9 \begin{array}{c} ~ & 9 & \cancel{\textcolor{red}{6}}~{5} \to & 18 \\ - & ~ & 8~~ & 9 \\ \hline ~ & ~ & ~ & 9 \\ \end{array}

  • Subtract the tens column:
    After borrowing, the tens column becomes 585 - 8 not possible, so borrow 1 from the hundreds column.

  • After borrowing, the tens column becomes 158=715 - 8 = 7.

 amp;9 8amp;15amp;8amp; amp;8amp;9 amp; amp;7 \begin{array}{c} ~ & \cancel{\textcolor{red}{9}}~ 8\to &{15} & 8 \\ - & ~ & 8 & 9 \\ \hline ~ & ~ & 7 \\ \end{array}

  • Subtract the hundreds column:
    Now simply 80=88 - 0 = 8 since there is nothing to subtract.

 amp;8amp; amp; amp; amp; amp; amp;8amp;7amp;9 \begin{array}{c} ~ & 8 & ~ & ~ \\ - & ~ & ~ & ~ \\ \hline &8 & 7 & 9 \\ \end{array}

Therefore, the solution to the problem is 879 879 .

Answer

879