Verify if (ab+c)/(c+ab) = 1: Rational Expression Analysis

Rational Expression Evaluation with Equivalent Forms

Indicate whether true or falseab+cc+ab=1 \frac{a\cdot b+c}{c+a\cdot b}=1

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:10 Our goal is to check if the equation is correct.
00:14 We'll apply the commutative law. So, let's rearrange the terms in the expression.
00:27 Now, we reduce what we can. After simplifying the fraction, we get one.
00:32 Next, let's compare the final expressions.
00:35 And there you have it. That's the solution to the problem!

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Indicate whether true or falseab+cc+ab=1 \frac{a\cdot b+c}{c+a\cdot b}=1

2

Step-by-step solution

Let's first examine the problem:

ab+cc+ab=?1 \frac{ab+c}{c+a b}\stackrel{?}{= }1 Looking at the expression on the left side, note that direct use of the distributive property in addition in the fraction's numerator (or alternatively in its denominator) gives us:

ab+cc+ab=c+abc+ab=1 \frac{a b+c}{c+a b}=\\ \frac{c+a b}{c+ab}=\\ 1 where in the final step we used the fact that dividing any number by itself always yields 1,

Therefore, the expressions on both sides of the (assumed) equality are indeed equal, meaning:

ab+cc+ab=c+abc+ab=!1 \frac{a b+c}{c+a b}= \frac{c+a b}{c+ab}\stackrel{!}{= }1

(In other words, an identity equation holds- which is true for all possible values of the parameter a,b,c a,b,c )

Therefore, the correct answer is answer A.

3

Final Answer

True

Key Points to Remember

Essential concepts to master this topic
  • Commutative Property: Addition order doesn't matter: ab + c = c + ab
  • Technique: Rewrite ab+cc+ab \frac{ab+c}{c+ab} as c+abc+ab \frac{c+ab}{c+ab}
  • Check: Any non-zero expression divided by itself equals 1 ✓

Common Mistakes

Avoid these frequent errors
  • Assuming different variable order means different values
    Don't think ab + c is different from c + ab = wrong conclusion that the fraction ≠ 1! Addition is commutative, so terms can be rearranged without changing value. Always recognize that ab + c and c + ab are identical expressions.

Practice Quiz

Test your knowledge with interactive questions

Determine if the simplification shown below is correct:

\( \frac{7}{7\cdot8}=8 \)

FAQ

Everything you need to know about this question

Why can I rearrange the terms in the numerator?

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Because of the commutative property of addition! This rule says a + b = b + a for any numbers or expressions. So ab + c is exactly the same as c + ab.

What if one of the variables equals zero?

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As long as the entire denominator doesn't equal zero, the expression is still valid. For example, if a = 0, we get 0+cc+0=cc=1 \frac{0+c}{c+0} = \frac{c}{c} = 1 (assuming c ≠ 0).

Is this always true for any values of a, b, and c?

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Yes! This is called an identity equation - it's true for all possible values of a, b, and c, as long as the denominator isn't zero (c + ab ≠ 0).

How do I know when a fraction equals 1?

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A fraction equals 1 when the numerator and denominator are identical. Since any non-zero number divided by itself equals 1, look for equivalent expressions in top and bottom.

What does it mean that this is an identity?

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An identity means the equation is always true regardless of what values you substitute for the variables. Unlike regular equations that have specific solutions, identities work for all allowed values.

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