Verify Point (3,36) on Function y = x²: Coordinate Check

Does the function y=x2 y=x^2 pass through the point where y = 36 and x = 3?

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Step-by-step video solution

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00:00 Does the point exist?
00:03 Let's substitute appropriate values according to the given data, and solve to find the point
00:11 Let's calculate the exponent
00:18 It seems the values don't match
00:23 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

Does the function y=x2 y=x^2 pass through the point where y = 36 and x = 3?

2

Step-by-step solution

To determine if the function y=x2 y = x^2 passes through the point (3,36) (3, 36) , we need to verify whether substituting x=3 x = 3 results in y=36 y = 36 .

Substitute x=3 x = 3 into the function:

  • The function is y=x2 y = x^2 .
  • Substitute x=3 x = 3 : y=32 y = 3^2
  • Calculate the value: y=9 y = 9

The calculated value of y y when x=3 x = 3 is 9 9 . We compare this value to the given y=36 y = 36 .

Since 936 9 \neq 36 , the function y=x2 y = x^2 does not pass through the point (3,36) (3, 36) .

Therefore, the correct answer is: No.

3

Final Answer

No

Practice Quiz

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What is the value of y for the function?

\( y=x^2 \)

of the point \( x=2 \)?

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