Solve y = x²: Finding Points Where y Equals 4

Given the function:

$y=x^2$

Is there a point for ? $y=4$?

To determine if there is a point on the graph of the parabola $y = x^2$ where $y = 4$, we need to find values of $x$ that satisfy the equation $x^2 = 4$.

Let's solve the equation step by step:

• Set the equation: $x^2 = 4$.
• Take the square root of both sides to solve for $x$:
• $x = \sqrt{4}$ or $x = -\sqrt{4}$.
• This gives us $x = 2$ or $x = -2$.

Therefore, the points on the graph where $y = 4$ are $(2, 4)$ and $(-2, 4)$.

This matches the provided correct answer of $(2, 4)$ and $(-2, 4)$.

Therefore, the correct solution is the point set $(2, 4)$ and $(-2, 4)$.