Verify the Equality: (14+a)(a-2) = -2a²+12a-28

To solve this problem, let's scrutinize the expression $(14+a)(a-2)$ by expanding it:

• Distribute each term in the first parenthesis with each term in the second parenthesis:
• $(14+a)(a-2) = 14 \cdot a + 14 \cdot (-2) + a \cdot a + a \cdot (-2)$
• Simplify each part: $14a - 28 + a^2 - 2a$
• Combine like terms: $a^2 + 12a - 28$

Now, compare this expanded and simplified expression $a^2 + 12a - 28$ to the given expression on the right-hand side, $-2a^2 + 12a - 28$.

Observe that the coefficient of $a^2$ is $1$ in our expansion but $-2$ in the right-hand side expression.

Therefore, the equality is incorrect due to the differing coefficients of $a^2$ in the expressions.

Hence, the correct choice is: No, due to the coefficient of $a^2$.