Determine if the simplification below is correct:
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Determine if the simplification below is correct:
We will divide the fraction exercise into two different multiplication exercises.
As this is a multiplication exercise, you can use the substitution property:
Therefore, the simplification described is false.
Incorrect
Complete the corresponding expression for the denominator
\( \frac{12ab}{?}=1 \)
Think of it this way: if you have 21 cookies and divide them into groups of 21, you get exactly 1 group. That's why !
Then you'd calculate each part separately: . Since 15 ≠ 14, this fraction cannot be simplified to 1.
A fraction equals 1 when the numerator and denominator are identical. Always calculate both parts first, then compare: if they match, the answer is 1!
No! A fraction only equals 0 when the numerator is 0 and the denominator is non-zero. Here, both the numerator and denominator equal 21, so the result is 1.
There's no difference - multiplication is commutative! So 3×7 = 7×3 = 21 whether it's on top or bottom of the fraction.
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