Examples with solutions for Sum and Difference of Angles: System of equations

Exercise #1

Below is the triangle ABC.

∢C+∢A=2(∢A+∢B) ∢C+∢A=2(∢A+∢B)

∢A=∢B ∢A=∢B

Calculates the size of angle ∢A ∢A .

AAACCCBBB

Video Solution

Step-by-Step Solution

To approach the problem, follow these steps:

  • Step 1: Establish and simplify the given equation.

  • Step 2: Use properties of triangle angles to form additional equations.

  • Step 3: Solve the equations to find ∠A \angle A .

Step 1: We're given ∠C+∠A=2(∠A+∠B) \angle C + \angle A = 2(\angle A + \angle B) .

Substitute ∠B=∠A \angle B = \angle A :

∠C+∠A=2(∠A+∠A)=4∠A\angle C + \angle A = 2(\angle A + \angle A) = 4\angle A.

Step 2: Use the triangle angle sum property:

∠A+∠B+∠C=180∘\angle A + \angle B + \angle C = 180^\circ.

Since ∠B=∠A \angle B = \angle A , we have:

∠A+∠A+∠C=180∘ \angle A + \angle A + \angle C = 180^\circ , simplifying to 2∠A+∠C=180∘ 2\angle A + \angle C = 180^\circ .

Step 3: Solve the System:

  • From 2∠A+∠C=180∘ 2\angle A + \angle C = 180^\circ , express ∠C \angle C as:

  • ∠C=180∘−2∠A\angle C = 180^\circ - 2\angle A.

  • Substitute into the equation ∠C+∠A=4∠A \angle C + \angle A = 4\angle A :

  • (180∘−2∠A)+∠A=4∠A (180^\circ - 2\angle A) + \angle A = 4\angle A .

  • Simplify: 180∘−∠A=4∠A 180^\circ - \angle A = 4\angle A .

  • Add ∠A\angle A to both sides: 180∘=5∠A 180^\circ = 5\angle A .

  • Solving for ∠A\angle A, we get: ∠A=180∘5\angle A = \frac{180^\circ}{5}.

  • Thus, ∠A=36∘\angle A = 36^\circ.

Answer

36°