Examples with solutions for Solving Equations by using Addition/ Subtraction: Combining like terms

Exercise #1

Find the value of the parameter X

−7+3x−8x=9+3−5x -7+3x-8x=9+3-5x

Video Solution

Step-by-Step Solution

To solve this equation for x x , we will follow these steps:

  • Simplify both sides of the equation by combining like terms.
  • Rearrange the equation to isolate the variable x x .
  • Analyze the resultant equation to determine the solution.

Let's break it down:

Step 1: Simplify the left side:
The left side of the equation is −7+3x−8x -7 + 3x - 8x . Combine the like terms 3x 3x and −8x-8x:
−7+(3x−8x)=−7−5x -7 + (3x - 8x) = -7 - 5x

Step 2: Simplify the right side:
The right side of the equation is 9+3−5x 9 + 3 - 5x . Combine the constant terms 9 9 and 3 3 :
(9+3)−5x=12−5x (9 + 3) - 5x = 12 - 5x

Step 3: Set the simplified equation:
Now the equation is:
−7−5x=12−5x -7 - 5x = 12 - 5x

Step 4: Analyze the equation:
If we attempt to isolate x x by adding 5x 5x to both sides, we get:
−7=12 -7 = 12

This statement is false. Since the manipulation leads to a false statement without any variable x x , the original equation has no solution.

Therefore, the equation cannot be true for any real number value of x x . Thus, the correct answer is: no solution.

Answer

No solution

Exercise #2

Solve for X:

4x−7=x+5 4x - 7 = x + 5

Video Solution

Step-by-Step Solution

To solve forx x , first, get all terms involving x x on one side and constants on the other. Start from:

4x−7=x+5 4x - 7 = x + 5

Subtract x x from both sides to simplify:

3x−7=5 3x - 7 = 5

Add 7 to both sides to isolate the terms withx x :

3x=12 3x = 12

Divide each side by 3 to solve forx x :

x=4 x = 4

Thus, x x is 4 4 .

Answer

4 4

Exercise #3

3x+4+8x−15=0 3x+4+8x-15=0

x=? x=\text{?}

Video Solution

Step-by-Step Solution

To solve the equation 3x+4+8x−15=0 3x + 4 + 8x - 15 = 0 , we begin by combining the terms that involve x x and the constant terms:

Step 1: Combine like terms.
The terms involving x x are 3x 3x and 8x 8x . Adding these yields:

11x 11x

The constant terms are +4 +4 and −15-15. Combining these gives:

+4−15=−11 +4 - 15 = -11

Thus, the equation becomes:

11x−11=0 11x - 11 = 0

Step 2: Solve for x x .
To isolate x x , add 11 to both sides of the equation:

11x−11+11=0+11 11x - 11 + 11 = 0 + 11 11x=11 11x = 11

Now, divide both sides by 11:

x=1111 x = \frac{11}{11} x=1 x = 1

Therefore, the solution to the equation is x=1 x = 1 .

Answer

1 1

Exercise #4

4a+5−24+a=−2a 4a+5-24+a=-2a

a=? a=?

Video Solution

Step-by-Step Solution

To solve the equation 4a+5−24+a=−2a 4a + 5 - 24 + a = -2a , follow these steps:

  • Step 1: Start by combining like terms on the left side of the equation:

4a+a+5−24=−2a 4a + a + 5 - 24 = -2a

This simplifies to:

5a−19=−2a 5a - 19 = -2a

  • Step 2: Move all terms involving a a to one side of the equation and constant terms to the other side:

Add 2a 2a to both sides to collect all terms with a a :

5a+2a=19 5a + 2a = 19

This simplifies to:

7a=19 7a = 19

  • Step 3: Solve for a a by dividing both sides by 7:

a=197 a = \frac{19}{7}

Thus, the value of a a is 197 \frac{19}{7} , which can be written as a mixed number:

a=257 a = 2\frac{5}{7} .

Upon verifying with the given choices, the correct answer is choice 1: 257 2\frac{5}{7} .

Answer

257 2\frac{5}{7}

Exercise #5

m+3m−17m+6=−20 m+3m-17m+6=-20

m=? m=\text{?}

Video Solution

Step-by-Step Solution

To solve the problem, we will use the following steps:

  • Step 1: Simplify the equation by combining like terms.
  • Step 2: Isolate the variable m m using algebraic methods.
  • Step 3: Solve for m m and verify the solution.

Let's begin:

Step 1: Simplify the equation m+3m−17m+6=−20 m + 3m - 17m + 6 = -20 .
Combine the coefficients of m m :

(1+3−17)m+6=−20 (1 + 3 - 17)m + 6 = -20

This simplifies to:

−13m+6=−20 -13m + 6 = -20

Step 2: Isolate m m .
Subtract 6 from both sides:

−13m+6−6=−20−6 -13m + 6 - 6 = -20 - 6

Simplifies to:

−13m=−26 -13m = -26

Step 3: Solve for m m by dividing both sides by -13:

m=−26−13 m = \frac{-26}{-13}

The division simplifies to:

m=2 m = 2

Therefore, the solution to the problem is m=2 m = 2 , which corresponds to choice 2 in the given options.

Answer

2

Exercise #6

2y⋅1y−y+4=8y 2y\cdot\frac{1}{y}-y+4=8y

y=? y=\text{?}

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Simplify the term 2y⋅1y 2y \cdot \frac{1}{y}
  • Rearrange the equation to group similar terms
  • Solve for y y

Now, let's work through each step:

Step 1: Simplify the expression 2y⋅1y 2y \cdot \frac{1}{y} .

The term 2y⋅1y 2y \cdot \frac{1}{y} simplifies directly to 2 2 since y y in the numerator and denominator cancel each other out assuming y≠0 y \neq 0 . Therefore, the equation becomes:

2−y+4=8y 2 - y + 4 = 8y

Step 2: Combine like terms on the left-hand side:

2+4=6 2 + 4 = 6 , so the equation now is 6−y=8y 6 - y = 8y .

Step 3: Rearrange the equation to isolate y y on one side. Add y y to both sides to get rid of the negative y y :

6=8y+y 6 = 8y + y

This simplifies to:

6=9y 6 = 9y

Step 4: Solve for y y by dividing both sides by 9:

y=69 y = \frac{6}{9}

Simplify the fraction to get:

y=23 y = \frac{2}{3}

Therefore, the solution to the problem is 23 \frac{2}{3} .

Answer

23 \frac{2}{3}

Exercise #7

2x+4+28−3x=x 2x+4+28-3x=x

x=? x=?

Video Solution

Step-by-Step Solution

To solve this problem, we will simplify and solve the linear equation step-by-step:

1. Start with the given equation:
2x+4+28−3x=x 2x + 4 + 28 - 3x = x

2. Combine like terms on the left side:
(2x−3x)+4+28=x (2x - 3x) + 4 + 28 = x

3. This simplifies to:
−x+32=x -x + 32 = x

4. Move all terms involving x x to one side of the equation by adding x x to both sides:
32=2x 32 = 2x

5. Finally, divide both sides by 2 to solve for x x :
x=322 x = \frac{32}{2}

6. Simplify to get the solution:
x=16 x = 16

Therefore, the solution to the problem is x=16 \mathbf{x = 16} .

Answer

16