Solving Equations by using Addition/ Subtraction: More than two fractions

We begin by placing parentheses around the two multiplication exercises:

$(20\times y)+(8\times2)-7=14$

We then solve the exercises within the parentheses:

$20y+16-7=14$

We simplify:

$20y+9=14$

We move the sections:

$20y=14-9$

$20y=5$

We divide by 20:

$y=\frac{5}{20}$

$y=\frac{5}{5\times4}$

We simplify:

$y=\frac{1}{4}$

To solve this problem, we will simplify and solve the linear equation step-by-step:

1. Start with the given equation:
$2x + 4 + 28 - 3x = x$

2. Combine like terms on the left side:
$(2x - 3x) + 4 + 28 = x$

3. This simplifies to:
$-x + 32 = x$

4. Move all terms involving $x$ to one side of the equation by adding $x$ to both sides:
$32 = 2x$

5. Finally, divide both sides by 2 to solve for $x$:
$x = \frac{32}{2}$

6. Simplify to get the solution:
$x = 16$

Therefore, the solution to the problem is $\mathbf{x = 16}$.