Examples with solutions for Parabola of the form y=x²: Write a function that expresses..

Exercise #1

A square has a side length of a.

Choose the function that expresses the perimeter of the square.

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Video Solution

Step-by-Step Solution

To find the perimeter of the square with side length a a , we use the standard formula for the perimeter of a square:

P=4×(side length)=4a P = 4 \times (\text{side length}) = 4a

This straightforward multiplication tells us that the perimeter is four times the side length because a square has four equal sides.

Therefore, the function that expresses the perimeter of the square is:

y=4a y = 4a

Among the given choices, the correct expression corresponding to this calculation is: y=4a y = 4a .

Thus, the solution to this problem is y=4a y = 4a .

Answer

y=4a y=4a

Exercise #2

A square has a side length of a.

Which function expresses the area of the square?

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Video Solution

Step-by-Step Solution

To determine the area of a square given its side length, we utilize the fundamental formula for the area of a square:

  • Step 1: Recall that the area A A of a square with side length a a is given by the formula A=a2 A = a^2 .
  • Step 2: Translate this into a function form, identifying the area as y y .
  • Step 3: Write the function expressing the area: y=a2 y = a^2 .

To conclude, the area of the square can be expressed as the function y=a2 y = a^2 .

Out of the provided choices, the correct expression for the area of the square as a function of the side length a a is Choice 4: y=a2 y = a^2 .

Answer

y=a2 y=a^2

Exercise #3

A square has a side length of a.

Choose the function that expresses the area of the shaded triangle.

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Video Solution

Step-by-Step Solution

To solve the problem, we will calculate the area of the triangle within a square of side length a a .

Since the triangle is formed by a diagonal of the square, its base and height are both equal to the side length a a of the square. Thus, base = a a and height = a a .

Using the formula for the area of a triangle, we have:

Area of the triangle=12×base×height=12×a×a=12×a2 \text{Area of the triangle} = \frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times a \times a = \frac{1}{2} \times a^2

This simplifies to a22\frac{a^2}{2}.

Therefore, the function that expresses the area of the shaded triangle is a22\frac{a^2}{2}, matching the choice with the answer: y=a22 y=\frac{a^2}{2} .

The solution to the problem is y=a22 y=\frac{a^2}{2} .

Answer

y=a22 y=\frac{a^2}{2}

Exercise #4

A square has sides measuring a.

Choose the function that expresses the length of the square's diagonal.

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Video Solution

Step-by-Step Solution

To find the length of the diagonal of a square with side length a a , we will use the Pythagorean theorem.

A diagonal divides a square into two congruent right-angled triangles. The legs of these triangles are the sides of the square, both with length a a . The diagonal then serves as the hypotenuse.

According to the Pythagorean theorem, the hypotenuse c c of a right triangle with legs a a is found via:

  • c=a2+a2 c = \sqrt{a^2 + a^2}

Simplifying inside the square root gives us:

  • c=2a2 c = \sqrt{2a^2}

We can further simplify this expression:

  • c=2a2=2a c = \sqrt{2} \cdot \sqrt{a^2} = \sqrt{2}a

Thus, the length of the diagonal is expressed by the function y=2a y = \sqrt{2}a .

In this problem, this solution corresponds to choice 1, which is y=2a y = \sqrt{2}a .

The chosen answer is correct as verified by the application of the Pythagorean theorem to a square.


Therefore, the correct function for the diagonal is y=2a y = \sqrt{2}a .

Answer

y=2a y=\sqrt{2}a

Exercise #5

A circle has a radius of a.

Choose the function that expresses its circumference.

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Video Solution

Step-by-Step Solution

The goal of this problem is to find the function that represents the circumference of the circle when the radius is a a .

The formula for the circumference of a circle is:

  • C=2πr C = 2\pi r

We are given that the radius r r is a a .

Using the formula C=2πr C = 2\pi r , substitute a a for r r :

C=2πa C = 2\pi a

Thus, the function that expresses the circumference of the circle is:

y=2πa y = 2\pi a

Among the given choices, y=2πa y = 2\pi a corresponds to choice number 4.

Answer

y=2πa y=2\pi a

Exercise #6

A circle has a radius a.

Choose the function that expresses the area of the circle.

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Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Identify the formula needed to compute the area of a circle.
  • Substitute the given radius into the formula.
  • Simplify the expression to match with the provided choices.

Now, let's work through the solution:

Step 1: The problem gives us the radius of the circle as a a .

Step 2: We'll apply the formula for the area of a circle:
A=πr2 A = \pi r^2

Step 3: Substitute r=a r = a :
A=πa2 A = \pi a^2

Therefore, the function expressing the area of the circle is y=πa2\boxed{y = \pi a^2}.

Answer

y=πa2 y=\pi a^2