Parabola y=x² Practice Problems with Step-by-Step Solutions
Master parabola functions y=x², y=-x², and y=ax² with interactive practice problems. Learn vertex, axis of symmetry, and graphing techniques through guided exercises.
📚Master Parabola Functions Through Targeted Practice
Graph basic parabola functions y=x² and identify key characteristics
Determine vertex and axis of symmetry for parabolas of form y=ax²
Analyze increasing and decreasing intervals for quadratic functions
Find positivity and negativity sets for parabola equations
Compare opening width changes when coefficient 'a' varies
Examples with solutions for Parabola of the form y=x²
Step-by-step solutions included
Exercise #1
What is the value of y for the function?
y=x2
of the point x=2?
Step-by-Step Solution
To solve this problem, we'll follow these steps:
Step 1: Substitute the given value of x into the equation.
Step 2: Perform the calculation to find y.
Now, let's work through each step:
Step 1: The given equation is y=x2. We need to substitute x=2 into this equation.
Step 2: Substitute to get y=(2)2. Calculate 2×2=4.
Therefore, the value of y when x=2 is y=4.
Hence, the solution to the problem is y=4.
Answer:
y=4
Video Solution
Exercise #2
What is the value of y for the function?
y=x2
of the point x=6?
Step-by-Step Solution
To solve this problem, we'll follow these steps:
Step 1: Identify the value given for x.
Step 2: Substitute the given x value into the function.
Step 3: Calculate the resulting value for y.
Now, let's work through each step:
Step 1: The problem states that x=6.
Step 2: Using the function y=x2, we substitute x=6.
Step 3: Perform the calculation: y=62.
Calculating 62, we get 36.
Therefore, for the function y=x2, when x=6, the value of y is y=36.
Answer:
y=36
Video Solution
Exercise #3
Complete:
The missing value of the function point:
f(x)=x2
f(?)=16
Step-by-Step Solution
To solve this problem, we'll follow these steps:
Step 1: Set up the equation from the function definition.
Step 2: Solve the equation by taking the square root of both sides.
Step 3: Identify all possible values for x.
Step 4: Compare with the given answer choices.
Now, let's work through each step:
Step 1: We start with the equation given by the function f(x)=x2. We know f(?)=16, so we can write:
x2=16
Step 2: To solve for x, we take the square root of both sides of the equation:
x=±16
Step 3: Solve for 16:
The square root of 16 is 4, so:
x=4 or x=−4
This gives us the two solutions: x=4 and x=−4.
Step 4: Compare these solutions to the answer choices. The correct choice is:
f(4) and f(−4)
Therefore, the solution to the problem is f(4) and f(−4).
Answer:
f(4)f(−4)
Video Solution
Exercise #4
What is the value of X for the function?
y=x2
of the point y=4?
Step-by-Step Solution
To solve this problem, we'll follow these steps:
Step 1: Set the equation of the function with the given point, x2=4.
Step 2: Solve for x by taking the square root of both sides. This accounts for both the positive and negative solutions.
Step 3: Evaluate the expression to find the solutions.
Now, let's work through each step:
Step 1: Set up the equation based on the given information:
We have x2=4.
Step 2: Solve by taking the square root of both sides:
Taking the square root, we get x=±4.
Step 3: Simplify to find the values of x:
The square root of 4 is 2, thus x=2 and x=−2.
Therefore, the solutions for x are x=2 and x=−2.
The correct answer is choice Answers a + b, which corresponds to having solutions x=2 and x=−2.
Answer:
Answers a + b
Video Solution
Exercise #5
What is the value of X for the function?
y=x2
of the point y=16?
Step-by-Step Solution
To solve this problem, let's find the steps required to determine x when y=16 in the function y=x2:
Step 1: Substitute the given y into the equation to get x2=16.
Step 2: To solve x2=16, take the square root of both sides, remembering to include both positive and negative roots. This yields x=±16.
Step 3: Simplify to find x=±4, which gives the solutions x=4 and x=−4.
Thus, the value(s) of x that satisfy y=16 in the function y=x2 are x=4 and x=−4.
Therefore, the solution to the given problem is x=4,x=−4.
Answer:
x=4,x=−4
Video Solution
Frequently Asked Questions
Everything you need to know about Parabola of the form y=x²
What is the vertex of the parabola y=x²?
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The vertex of y=x² is at the point (0,0). This is the minimum point of the parabola since it opens upward, creating a 'happy face' shape.
How do you find the axis of symmetry for y=x²?
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The axis of symmetry for y=x² is the vertical line x=0 (the y-axis). This line divides the parabola into two identical halves that mirror each other.
What happens to the parabola when you change from y=x² to y=-x²?
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When you change from y=x² to y=-x², the parabola flips upside down. It becomes a 'sad face' function with a maximum at (0,0) instead of a minimum, and opens downward instead of upward.
How does the coefficient 'a' affect the shape of y=ax²?
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The coefficient 'a' controls the width of the parabola opening. When |a| increases, the parabola becomes narrower (closer to the axis of symmetry). When |a| decreases, the parabola becomes wider (further from the axis of symmetry).
Where is the function y=x² increasing and decreasing?
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For y=x², the function decreases on the interval x<0 (left side of vertex) and increases on the interval x>0 (right side of vertex). The vertex at x=0 is the turning point between decreasing and increasing behavior.
What are the positive and negative regions of y=x²?
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For y=x², the function is positive for all x-values except x=0 where y=0. There are no negative y-values since the entire parabola lies above or on the x-axis.
Why is y=x² called a quadratic function?
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y=x² is called a quadratic function because the highest power of the variable x is 2 (squared). It's the most basic form of a quadratic with coefficients a=1, b=0, and c=0 in the standard form y=ax²+bx+c.
How do you graph y=ax² step by step?
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To graph y=ax²: 1) Plot the vertex at (0,0), 2) Draw the axis of symmetry at x=0, 3) Choose x-values and calculate corresponding y-values, 4) Plot points symmetrically on both sides of the axis, 5) Connect points with a smooth U-shaped curve (upward if a>0, downward if a<0).
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