Special Cases (0 and 1, Inverse, Fraction Line): Complete the missing number

To solve this problem, we'll follow these steps:

• Step 1: Identify potential values for the missing number $\square$.
• Step 2: Verify if it fits the equation $☐^7 = 1$.
• Step 3: Consider alternative numbers from intuitive mathematics.

Now, let's work through each step:
Step 1: We hypothesize that the number could be 1, given that raising 1 to any power yields 1.
Step 2: Verify $(1)^7 = 1$, which is true since any real number 1 raised to any integer power remains 1.
Step 3: As a check for understanding: with odd powers greater than 1, attempts with $-1$ as choices lead to $(-1)^7 = -1$, which doesn’t meet the requirement, reinforcing $☐ = 1$.

Therefore, the solution to the problem is 1, choice number 4.

We place the multiplication exercise inside of the parenthesis:

$(5\times17)-112-\frac{x}{14}=-27.5$

We solve the multiplication exercise and then subtract:

$85-112-\frac{x}{14}=-27.5$

$-27-\frac{x}{14}=-27.5$

We swap sections:

$-\frac{x}{14}=-27.5+27$

$-\frac{x}{14}=-\frac{1}{2}$

We multiply by 14:

$-x=-\frac{1}{2}\times14$

$-x=-7$

We multiply by -1

$x=7$