Special Cases (0 and 1, Inverse, Fraction Line): Using fractions

According to the order of operations, we first place the multiplication operation inside parenthesis:

$(7\times1)+\frac{1}{2}=$

Then, we perform this operation:

$7\times1=7$

Finally, we are left with the answer:

$7+\frac{1}{2}=7\frac{1}{2}$

According to the order of operations, we will solve the exercise from left to right since it only contains multiplication and division operations:

$\frac{6}{3}=2$

$2\times1=2$

According to the order of operations, since the exercise only involves addition operations, we will solve the problem from left to right:

$\frac{1}{2}+0=\frac{1}{2}$

$\frac{1}{2}+\frac{1}{2}=\frac{1}{1}=1$

According to the order of operations, we will solve the exercise from left to right.

$\frac{1}{2}=0.5$

$0.5+0.5=1$

$1-0=1$

According to the rules of the order of operations, we should first solve the exercise from left to right since there are only multiplication and division operations present:

$1\times\frac{1}{2}=\frac{1}{2}$

$\frac{1}{2}:2=\frac{1}{4}$

According to the order of operations, we must solve the exercise from left to right since it contains only multiplication operations:

$\frac{3}{2}\times1=\frac{3}{2}$

$\frac{3}{2}\times\frac{1}{3}=$

Then, we will multiply the 3 by 3 to get:

$\frac{1}{2}\times1=\frac{1}{2}$

According to the order of operations rules, we must first solve the fraction:

$\frac{6}{3}=2$

Resulting in the following expression:

$2-1=1$

Let's begin by multiplying the numerator:

$12+8=20$

We should obtain the fraction written below:

$\frac{20}{5}$

Let's now reduce the numerator and denominator by 5 and we should obtain the following result:

$\frac{4}{1}=4$

According to the order of operations rules, due to the fact that the exercise only involves addition and subtraction, we will solve the problem from left to right:

$\frac{1}{4}+0=\frac{1}{4}$

$\frac{1}{4}-\frac{1}{4}=0$

$0-0=0$

According to the order of operations, we will first solve the fraction exercise:

$\frac{20}{3+2}=\frac{20}{5}=4$

$4+6=10$

According to the order of operations, we will first solve the fraction exercise:

$\frac{16-10}{2}=\frac{6}{2}=3$

$20-3=17$

Let's first look at the numerator of the fraction. We will convert it to an addition exercise containing two fractions:

$1+\frac{1}{2}$

$1=\frac{2}{2}$

This leaves us with:

$\frac{\frac{2}{2}+\frac{1}{2}}{6}=$

$\frac{\frac{2+1}{2}}{6}=$

$\frac{\frac{3}{2}}{\frac{6}{1}}=$

Let's now multiply the two fractions together—numerator by numerator and denominator by denominator:

$\frac{1\times3}{2\times6}=$

$\frac{3}{12}=\frac{3}{3\times4}$

Finally, simplify:

$\frac{3}{3\times4}=\frac{1}{4}$

$\frac{1}{4}=0.25$

According to the order of operations, first we'll solve the fraction:

$\frac{45}{9}=5$

$25+5=30$

We will use the formula:

$\frac{a}{a}=1$

Therefore the answer is 1