Calculate y given that and .
Calculate y given that \( x=2 \) and \( y=x \).
Find a y when \( x=2 \)
\( y=5x \)
Find a y when x=2
\( y=\frac{1}{2}x \)
Find a y when x=2
\( y=x-8 \)
Calculate y given that \( X=2 \) and \( y=0.8x \).
Calculate y given that and .
We are given the equation y=x
We are also given the value of x,
x=2
Therefore, we will insert the given value into the equation
y=2
And that's the solution!
Find a y when
To solve this problem, we'll follow these steps:
Now, let's work through each step:
Step 1: We start with the equation .
Step 2: Substitute into this equation:
.
Step 3: Perform the multiplication:
.
Therefore, the solution to the problem is .
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Find a y when x=2
To solve this problem, we will follow these steps:
Now, let's work through each step:
Step 1: The equation provided is . We need to find the value of when .
Step 2: Substitute into the equation:
Simplifying this expression gives:
Therefore,
.
The calculated value of is .
Find a y when x=2
To solve the problem, we will follow these steps:
Step 1: Substitute the given value of into the equation .
Step 2: Simplify the expression to find the corresponding value of .
Now, let's apply these steps:
Step 1: Given the equation , we substitute :
Step 2: Simplify the expression:
Thus, the value of when is .
Therefore, the solution to the problem is .
Calculate y given that and .
To solve this problem, we will follow these steps:
Step 1: Identify the given information
Step 2: Apply the formula
Step 3: Perform the calculation
Now, let's work through each step:
Step 1: The problem gives us that and the relationship between and is .
Step 2: We will use the formula .
Step 3: Substituting into the formula, we get .
The calculation is as follows:
.
Therefore, the solution to the problem is .
1.6
Find a \( y \) when x=2
\( y=30x-6 \)
Find a y when x=2
\( y=8x+1 \)
Calculate y given that \( x=2 \) and \( y=4(2-6x) \).
Find a y when x=2
\( y=18(x-2) \)
Find \( y \) when \( x=2 \)
\( y=\frac{2}{5}x+2 \)
Find a when x=2
To solve this problem, we'll follow these steps:
Substitute the given value of into the equation .
Perform the necessary arithmetic to solve for .
Now, let's work through these steps:
Step 1: The problem gives us and the equation .
Step 2: Substitute into the equation:
Step 3: Calculate the expression:
The solution to the problem is .
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Find a y when x=2
To solve this problem, we’ll follow these steps:
Let’s work through each step:
Step 1: Our given equation is . We substitute into the equation:
Step 2: Calculate the expression:
Therefore, when , the value of is .
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Calculate y given that and .
To solve for , we will proceed with these steps:
Now, let's work through the steps:
Step 1: Substitute into the equation:
Step 2: Simplify the expression within the parentheses:
Step 3: Calculate the value of by multiplying by 4:
Therefore, the value of is .
This solution corresponds to the choice:
Choice 3:
Find a y when x=2
To solve this problem, we need to substitute into the given expression for .
Let's perform these steps:
Step 1: The expression given is .
Step 2: Substitute into the expression:
.
Step 3: Simplify the expression:
Since , we have .
Therefore, when , the value of is .
Find when
In this exercise, we are given the value of X, so we will substitute it into the formula.
It's important to remember that between an unknown and a number there is a multiplication sign, therefore:
Let's convert to a decimal fraction:
And that's the solution!
Find a y when x=2
\( y=5.6x-2.1 \)
Find a y when x=2
\( y=2+6x \)
Find a y when x=2
To solve this problem, follow these steps:
Now, let's work through each step:
Step 1: The equation given is . We need to find when .
Step 2: Substitute into the equation:
.
Step 3: Calculate by performing the arithmetic:
First, calculate the multiplication: .
Then, subtract 2.1 from 11.2: .
Therefore, the solution to the problem is .
9.1
Find a y when x=2
To solve this problem, we'll substitute the given value of into the equation .
1. Substitute into the equation:
2. Perform the multiplication :
3. Add the result to 2:
Thus, when , the value of is .
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