Additional Arithmetic Rules: Using multiple rules

$35-(82-39:(3\cdot2))=\text{?}$

$-40\frac{1}{2}$

$124-(38-92)-(56+33)=\text{?}$

89

$78-(39-47)-(95+3:\frac{3}{5})=\text{?}$

$-14$

$-55-(-94-(-32))+12:\frac{3}{4}=\text{?}$

$23$

$130:\frac{10}{2x}-(23x-204)=\text{?}$

$3x+204$

$300:(20\cdot8)-(13+200)=\text{?}$

$-211\frac{1}{8}$

$28:(210:15)-(12+42)=\text{?}$

$-52$

$39:(x\cdot3)+\frac{y}{x}:\frac{y}{4}=\text{?}$

$\frac{17}{x}$

$35-(400:\frac{20}{13}-12)=\text{?}$

$-213$

$1-(4\cdot13\cdot7:\frac{2}{26}-13\cdot13\cdot7\cdot4)=?$

1

$3x-(y\cdot z+3z:\frac{z}{x})=\text{?}$

$-yz$

$48:\frac{10}{x}-(x+5)=\text{?}$

$3.8x-5$

$35:(7\cdot5)-(2+9:\frac{3}{2})=\text{?}$

7-

$79-(35-(-9))-(10+43)=\text{?}$

18-

$a:\frac{3}{n}+13b-(12b+na)=\text{?}$

$b-\frac{2}{3}an$

$84:(2\cdot7)-(63-2x)=\text{?}$

$2x-57$

$3x-((-12x)+4y)-7y:(2x\cdot12y)=\text{?}$

$15x-4y-\frac{7}{24x}$

$-38-((\text{-}14)-(-7))-3(7+4b)=\text{?}$

$-52-12b$

$49+2a-(54a+9a:(5a\cdot3))=\text{?}$

$48\frac{2}{5}-52a$

$17-(215-(314+95))=\text{?}$

$211$