3−(12a−(a:a14+12))=?
To solve this problem, follow these steps:
Start by simplifying the innermost operations and move outward:
- Step 1: Simplify the division inside the parentheses:
a:a14=14a⋅a=14a2
- Step 2: Substitute this back into the expression:
12a−(14a2+12)
- Step 3: Simplify inside the parenthesis:
12a−(14a2+12)=12a−14a2−12
- Step 4: Distribute the negative sign across the expression within parentheses:
3−(12a−14a2−12)=3−12a+14a2+12
- Step 5: Combine the constant terms:
3+12−12a+14a2=15−12a+14a2
Thus, the expression simplifies to 15−12a+14a2.
15−12a+14a2