# Division of Whole Numbers with Multiplication in Parentheses - Examples, Exercises and Solutions

### Division of whole numbers with multiplication in parentheses

For example:

$24 : (6\times2) =$

One way to solve this exercise will be to remove the parentheses. To do this, we must remember the rule that states that, in order to remove the parentheses, we must divide the whole number by each of the terms of the multiplication operation in parenthese.

That is, in our example:

$24:(6\times2)=$

$24 : 6 : 2 =$

$4 : 2 = 2$

## examples with solutions for division of whole numbers with multiplication in parentheses

### Exercise #1

$12:(2\times2)=$

### Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

$2\times2=4$

Now we divide:

$12:4=3$

$3$

### Exercise #2

$7-(4+2)=$

### Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

$4+2=6$

Now we solve the rest of the exercise:

$7-6=1$

$1$

### Exercise #3

$8-(2+1)=$

### Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

$2+1=3$

Now we solve the rest of the exercise:

$8-3=5$

$5$

### Exercise #4

$13-(7+4)=$

### Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

$7+4=11$

Now we subtract:

$13-11=2$

$2$

### Exercise #5

$38-(18+20)=$

### Step-by-Step Solution

According to the order of operations, first we solve the exercise within parentheses:

$18+20=38$

Now, the exercise obtained is:

$38-38=0$

$0$

### Exercise #6

$28-(4+9)=$

### Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

$4+9=13$

Now we obtain the exercise:

$28-13=15$

$15$

### Exercise #7

$55-(8+21)=$

### Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

$8+21=29$

Now we obtain the exercise:

$55-29=26$

$26$

### Exercise #8

$37-(4-7)=$

### Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

$4-7=-3$

Now we obtain:

$37-(-3)=$

Remember that the product of a negative and a negative results in a positive, therefore:

$-(-3)=+3$

Now we obtain:

$37+3=40$

$40$

### Exercise #9

$80-(4-12)=$

### Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

$4-12=-8$

Now we obtain the exercise:

$80-(-8)=$

Remember that the product of plus and plus gives us a positive:

$-(-8)=+8$

Now we obtain:

$80+8=88$

$88$

### Exercise #10

$100-(30-21)=$

### Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

$30-21=9$

Now we obtain:

$100-9=91$

$91$

### Exercise #11

$66-(15-10)=$

### Step-by-Step Solution

According to the order of operations rules, we first solve the expression in parentheses:

$15-10=5$

Now we get the expression:

$66-5=61$

$61$

### Exercise #12

$22-(28-3)=$

### Step-by-Step Solution

According to the order of operations, we first solve the exercise within parentheses:

$28-3=25$

Now we obtain the exercise:

$22-25=-3$

$-3$

### Exercise #13

$60:(5\times3)=$

### Step-by-Step Solution

We write the exercise in fraction form:

$\frac{60}{5\times3}$

We break down 60 into a multiplication exercise:

$\frac{20\times3}{5\times3}=$

We simplify the 3s and obtain:

$\frac{20}{5}$

We break down the 5 into a multiplication exercise:

$\frac{5\times4}{5}=$

We simplify the 5 and obtain:

$\frac{4}{1}=4$

$4$

### Exercise #14

$60:(10\times2)=$

### Step-by-Step Solution

We write the exercise in fraction form:

$\frac{60}{10\times2}=$

Let's separate the numerator into a multiplication exercise:

$\frac{10\times6}{10\times2}=$

We simplify the 10 in the numerator and denominator, obtaining:

$\frac{6}{2}=3$

$3$

### Exercise #15

$21:(30:10)=$

### Step-by-Step Solution

We will use the formula:

$a:(b:c)=a:b\times c$

Therefore, we will get:

$21:30\times10=$

Let's write the division exercise as a fraction:

$\frac{21}{30}=\frac{7}{10}$

Now let's multiply by 10:

$\frac{7}{10}\times\frac{10}{1}=$

We'll reduce the 10 and get:

$\frac{7}{1}=7$

$7$