Multiplication and Division of Signed Mumbers: Dividing numbers with different signs

Due to the fact that we are dividing a positive number by a negative number, the result must be a negative number:

$+:-=-$

Therefore:

$-(10:5)=-2$

Given that we are dividing a positive number by a negative number, the result must be a negative number:

$+:-=-$

First, let's convert 0.4 to a simple fraction:

$0.4=\frac{4}{10}$

Now we have the problem:

$-(24:\frac{4}{10})=$

Let's convert the division to multiplication, remembering to switch the numerator and denominator:

$-(24\times\frac{10}{4})=$

We'll simplify by 4 as follows:

$-(6\times10)=-6\times10=-60$

Firstly we need to realise that since we are dividing two negative numbers, the result must be a positive number.

$+:-=-$

Next, let's convert 0.05 into a simple fraction:

$-0.05=-\frac{5}{100}$

We are left with:

$-(3:\frac{5}{100})=$

Then let's convert the division into multiplication, remembering to switch the numerator and denominator:

$-(3\times\frac{100}{5})=$

Finally we can continue solving to find the answer:

$-(3\times20)=-60$

Since we are dividing a positive number by a negative number, the result must be a negative number:

$+:-=-$

First, let's convert the numbers in the exercise to simple fractions:

$0.9=-\frac{9}{10}$

$0.15=\frac{15}{100}$

Resulting in the following exercise:

$-(\frac{9}{10}:\frac{15}{100})=$

Let's convert the division to multiplication, don't forget to switch between numerator and denominator:

$-(\frac{9}{10}\times\frac{100}{15})=$

Let's reduce by 10 and obtain the following:

$-(9\times\frac{10}{15})=$

Let's combine into one exercise:

$-(\frac{9\times10}{15})=-\frac{90}{15}$

Let's break down 90 into a multiplication exercise:

$-\frac{3\times30}{15}=$

Let's reduce the numerator and denominator by 15 and obtain:

$-3\times2=-6$

Let's solve the exercise from left to right.

First, we'll write the division problem in the form of a fraction:

$\frac{200}{-200}\times200=$

We should note that we are dividing a positive number by a negative number, so the result will necessarily be a negative number:

$-\frac{200}{200}\times200=$

Let's simplify the 200 and we get:

$-200$

Let's begin by writing the two division exercises as a multiplication of two simple fractions:

$(38:(-4))\times(12:(-3))=$

$\frac{38}{-4}\times\frac{12}{-3}=$

Let's proceed to combine them into one exercise:

$\frac{38\times12}{-4\times-3}=$

Note that in the denominator of the fraction we are multiplying two negative numbers, therefore the result must be positive:

$\frac{38\times12}{4\times3}=$

Let's now break down the 12 in the fraction's numerator into a multiplication exercise:

$\frac{38\times4\times3}{4\times3}=$

Finally let's reduce the multiplication exercise 4X3 in the numerator and denominator and we should obtain the following:

$38$

Let's solve the exercise from left to right.

Note that we are first multiplying a negative number by a positive number, therefore the result must be a negative number:

$-13\times4=-52$

Now we got the exercise:

$-52:-8=$

Let's write the exercise as a simple fraction:

$\frac{-52}{-8}=$

Note that we are dividing between two negative numbers, therefore the result must be a positive number:

$\frac{52}{8}=$

Let's convert it to an addition exercise:

$6+\frac{4}{8}=$

Let's break down the 8 into a multiplication exercise:

$6+\frac{4}{4\times2}=$

Let's reduce the 4 in both eight and the fraction's denominator:

$6+\frac{1}{2}=6\frac{1}{2}$

Let's write the exercise in the following form:

$\frac{400\times(-4)}{-16}:-6=$

Let's factor -16 in the denominator as a multiplication exercise:

$\frac{400\times(-4)}{4\times(-4)}:-6=$

Let's reduce -4 in both the numerator and denominator and get:

$\frac{400}{4}:-6=$

Let's factor the 100 in the numerator as a multiplication exercise:

$\frac{100\times4}{4}:-6=$

Let's reduce the 4 in both the numerator and denominator and get:

$100:-6=$

Let's write the exercise as a fraction:

$\frac{100}{-6}=$

Note that we are dividing a positive number by a negative number, therefore the result must be negative.

Let's factor the 100 as an addition exercise:

$-\frac{96+4}{6}=$

Let's write the exercise in the following way:

$-(\frac{96}{6}+\frac{4}{6})=$

Let's solve the first fraction and in the second fraction let's factor the numerator and denominator as multiplication exercises:

$-(16+\frac{2\times2}{2\times3})=$

Let's reduce the 2 in both the numerator and denominator:

$-(16+\frac{2}{3})=$

Let's pay attention to the appropriate sign since we are multiplying by a negative number:

$-16\frac{2}{3}$