Addition, Subtraction, Multiplication and Division: Using parentheses

The problem to be solved is $0.6\times(1+2)=$. Let's go through the solution step by step, following the order of operations.

Step 1: Evaluate the expression inside the parentheses.
Inside the parentheses, we have $1+2$. According to the order of operations, we first solve expressions in parentheses. Thus, we have:

$1 + 2 = 3$

So, the expression simplifies to $0.6\times3$.

Step 2: Perform the multiplication.
With the parentheses removed, we now carry out the multiplication:

$0.6 \times 3 = 1.8$

Thus, the final answer is $1.8$.

To solve the expression $\frac{1}{3}+(2-1)$, we need to follow the order of operations, often abbreviated as PEMDAS (Parentheses, Exponents, Multiplication and Division (from left to right), Addition and Subtraction (from left to right)). This problem primarily involves parentheses and addition.

We'll start by solving the expression within the parentheses:

• The expression inside the parentheses is $(2-1)$. Subtracting, we get:

$2 - 1 = 1$

After solving the parentheses, the expression becomes:

$\frac{1}{3} + 1$

Next, we perform the addition:

• Since $1$ can be written as $\frac{3}{3}$ to have a common denominator with $\frac{1}{3}$, we add:

$\frac{1}{3} + \frac{3}{3} = \frac{1+3}{3} = \frac{4}{3}$

The fraction $\frac{4}{3}$ can also be expressed as a mixed number:

• $\frac{4}{3} = 1 \frac{1}{3}$ (where $1$ is the whole number and $\frac{1}{3}$ is the fractional part)

Thus, the correct answer is $1\frac{1}{3}$.

First, calculate the expression inside the parentheses: $3 + 1$ equals $4$.

Then multiply $0.4$ by $4$ to get $1.6$.