Addition, Subtraction, Multiplication and Division - Examples, Exercises and Solutions

According to the order of operations rules, we will solve the exercise from left to right since the only operations in it are addition and subtraction:

$10-3=7$

$7+7=14$

$14-5=9$

According to the rules of the order of operations, given that the exercise only involves subtraction and addition operations, we solve the exercise from left to right:

$3+2=5$

$5-1=4$

According to the rules of the order of operations, we will solve the exercise from left to right since it only has addition and subtraction operations:

$9-3=6$

$6+4=10$

$10-2=8$

According to the rules of the order of arithmetic operations, we will work to solve the exercise from left to right:

9+3=11

11-1=10

And this is the solution!

Division and multiplication are on the same level of order of operations,

therefore, when encountering such a case, we will always solve from left to right.

10*2=20

20/4=5

According to the rules of the order of operations, the exercise which contains both multiplication and division should be solved from left to right.

$30:5=6$

$6\times2=12$

According to the order of operations rules, we will solve the exercise from left to right since the only operations in it are addition and subtraction:

$90-2=88$

$88+9=97$

$97-8=89$

According to the rules of the order of operations, multiplication and division precede addition and subtraction.

We isolate the multiplication exercise in parentheses and solve.

$(7\times3)=21$

Now, the exercise we're left with is: $21+8-4-7=$

We solve the exercise from left to right. We isolate the next part of the expression with parentheses to avoid confusion$(21+8)=29$

Now, the exercise obtained is: $29-4-7=$

We continue solving from left to right and isolate the next part of the expression in parentheses.

$(29-4)=25$

Now, the expression obtained is: $25-7=18$

According to the rules of the order of operations, we first solve the multiplication exercise:

$3+8+(4\times3)=$

$4\times3=12$

Now, we solve the addition exercise from left to right:

$3+8+12=$

$11+12=23$

According to the order of operations, we put the multiplication and division exercise in parentheses:

$(15:5)+(4\times3)=$

Now we solve the parentheses:

$15:5=3$

$4\times3=12$

And we get the exercise:

$3+12=15$

According to the order of operations, we place the multiplication and division exercise within parentheses:

$(20:4)+(3\times2)=$

Now we solve the exercises within parentheses:

$20:4=5$

$3\times2=6$

And we obtain the exercise:

$5+6=11$

According to the rules of the order of arithmetic operations, we begin by enclosing the multiplication exercise inside parentheses:

$2-(5\times3)+4=$

We then solve the said exercise inside of the parentheses:

$5\times3=15$

We obtain the following:

$2-15+4=$

Lastly we solve the exercise from left to right:

$2-15=-13$

$-13+4=-9$

According to the order of operations rules, we first insert the multiplication and division exercises into parentheses:

$2+(4\times5:2)+3=$

Now let's solve the expression in parentheses from left to right:

$4\times5=20$

$20:2=10$

And we get the expression:

$2+10+3=$

Let's solve the expression from left to right:

$2+10=12$

$12+3=15$

Due to the fact that the exercise only involves addition and subtraction operations, we will solve it from left to right:

$25-6=19$

$19-9=10$

$10+7=17$

$17-3=14$

Due to the fact that the exercise only involves addition and subtraction operations, we will solve it from left to right:

$14-5=9$

$9-9=0$

$0+7=7$

$7+2=9$