Addition, Subtraction, Multiplication and Division: Addition, subtraction, multiplication and division

According to the rules of the order of arithmetic operations, we must first place the multiplication and division exercises within parentheses:

$5-(30:2\times3)+10=$

We then solve the exercise inside of the parentheses from left to right:

$30:2=15$

$15\times3=45$

We obtain the following exercise:

$5-45+10=$

Finally we solve the exercise from left to right:

$5-45=-40$

$-40+10=-30$

According to the rules of the order of arithmetic operations, we must first place the multiplication and division exercises within parentheses:

$(4\times7\times2:4)-(1\times9)=$

We then proceed to solve the exercise in parentheses from left to right:

$4\times7=28$

$28\times2=56$

$56:4=14$

We obtain the following exercise:

$14-9=5$

According to the order of operations rules, we first insert the multiplication and division exercises into parentheses:

$3+(4:2\times1)-9+4=$

We'll solve the exercise from left to right:

$4:2=2$

$2\times1=2$

And we'll obtain the following exercise:

$3+2-9+4=$

Since the exercise only contains subtraction operations, we'll solve it from left to right:

$3+2=5$

$5-9=-4$

$-4+4=0$

According to the rules of the order of arithmetic operations, we must first place multiplication and division exercises within parentheses:

$7+(3\times7)-(3\times4)+5=$

We then proceed to solve the exercise inside of the parentheses:

$3\times7=21$

$3\times4=12$

We obtain the following exercise:

$7+21-12+5=$

Lastly we solve the exercise from left to right:

$21+7=28$

$28-12=16$

$16+5=21$

According to the rules of the order of arithmetic operations, we begin by placing the multiplication and division exercises inside of parentheses:

$8+(3\times4)-2+1=$

We then solve the exercise within the parentheses:

$3\times4=12$

We obtain the following :

$8+12-2+1=$

Finally we solve the exercise from left to right:

$8+12=20$

$20-2=18$

$18+1=19$

According to the rules for the order of operations, we will isolate the multiplication and division exercises in parentheses:

$(14:2\cdot5:7)+12+25=$

We solve the exercise in parentheses from left to right:

$14:2=7$

$7\times5=35$

$35:7=5$

Now we obtain the exercise:

$5+12+25=$

We solve the exercise from left to right:

$5+12=17$

$17+25=42$

According to the order of operations rules, we'll place the division exercises in parentheses:

$(81:9:3)+18+27-10=$

Let's solve the expression in parentheses from left to right:

$81:9=9$

$9:3=3$

We should obtain the following expression:

$3+18+27-10=$

Let's solve the expression from left to right:

$3+18=21$

$21+27=48$

$48-10=38$

Given that, according to the rules of the order of operations, parentheses come first, we will first solve the exercise that appears within the parentheses.

$4\times2-\frac{9}{3}=$

We solve the multiplication exercise:

$4\times2=8$

We divide the fraction (numerator by denominator)$\frac{9}{3}=3$

And now the exercise obtained within the parentheses is$8-3=5$

Finally, we divide:$12:5=\frac{12}{5}$

According to the rules for the order of operations, we will isolate the multiplication operations in parentheses:

$(9\cdot5\cdot5)+7-5+82-2=$

We solve the exercise in parentheses from left to right:

$9\times5=45$

$45\times5=225$

Now, we obtain the exercise:

$225+7-5+82-2=$

We solve the exercise from left to right

$225+7=232$

$232-5=227$

$227+82=309$

$309-2=307$

In the first stage of the exercise, you need to calculate the multiplication.

$2\times\frac{1}{2}=\frac{2}{1}\times\frac{1}{2}=\frac{2}{2}=1$

From here you can continue with the rest of the addition and subtraction operations, from right to left.

$5-1+1=5$

According to the rules for the order of operations, we will place multiplication and division exercises in parentheses:

$(24:8:3)+(2\cdot6\cdot2)+19=$

We solve the division exercises in parentheses from left to right:

$24:8=3$

$3:3=1$

We solve the multiplication exercises in parentheses from left to right:

$2\times6=12$

$12\times2=24$

Now we get the exercise:

$1+24+19=$

We solve the exercise from left to right:

$1+24=25$

$25+19=44$

In the numerator we solve the square root exercise:

$\sqrt{49}=7$

In the denominator we solve the exercise within parentheses:

$(2+2\times3)=$

$2+6=8$

The exercise we now have is:

$\frac{21:7+2}{8-8}=$

We solve the exercise in the numerator of fractions from left to right:

$21:7=3$

$3+2=5$

We obtain the exercise:

$\frac{5}{8-8}=\frac{5}{0}$

Since it is impossible for the denominator of the fraction to be 0, it is impossible to solve the exercise.

We start by solving the exercise in the numerator and then solve the exercise in the denominator.

We know that multiplication and division operations come before addition and subtraction operations, so first we will divide 15:3 and then multiply the result by 2:

$15:3=5$

$12-5\times2=12-10=2$

The result of the numerator is 2 and now we will solve the exercise that appears in the denominator.

It is known that according to the rules of the order of operations, the exercise that appears between parentheses goes first, so we first solve the exercise$2+3=5$

$$Now, we solve the division exercise:$10:5=2$

The result we get in the denominator is 2.

Finally, divide the numerator by the denominator:

$\frac{2}{2}=1$