All Operations in the Order of Operations: Small Numbers

According to the rules of the order of operations, we will solve the exercise from left to right since it only has addition and subtraction operations:

$9-3=6$

$6+4=10$

$10-2=8$

Due to the fact that the exercise only involves addition and subtraction operations, we will solve it from left to right:

$14-5=9$

$9-9=0$

$0+7=7$

$7+2=9$

According to the rules of the order of arithmetic operations, we solve the exercise from left to right since it only has addition and subtraction operations:

$-7+5=-2$

$-2+2=0$

$0+1=1$

According to the order of operations rules, we must first solve the division problem, and subsequently the subtraction problem:

$3:4=\frac{3}{4}$

$11-\frac{3}{4}=10\frac{1}{4}$

According to the rules of the order of arithmetic operations, we must first solve the multiplication exercises.

We place them inside of parentheses in order to avoid confusion during the solution:

$2+(3\times6)-(3\times7)+1=$

We then solve the multiplication exercises:

$2+18-21+1=$

Lastly we solve the rest of the exercise from left to right:

$2+18=20$

$20-21=-1$

$-1+1=0$

According to the rules of the order of arithmetic operations, we must first solve the multiplication exercises.

We place them inside of parentheses to avoid confusion during the solution:

$4-(5\times7)+3=$

We then solve the multiplication exercises:

$4-35+3=$

Lastly we solve the rest of the exercise from left to right:

$4-35=-31$

$-31+3=-28$

Let's start with the part inside the parentheses. 

$2+2=4$
Then we will solve the exercise from left to right 

$8:2=4$
$4 × (4)=16$

The answer: $16$

According to the order of operations, we will first solve the multiplication exercises.

We will put them in parentheses so that we don't get confused later in the solution:

$25-(3\times4)+(4\times2)=$

Let's solve the multiplication exercises:

$3\times4=12$

$4\times2=8$

We get:

$25-12+8=$

Let's solve the exercise from left to right:

$25-12=13$

$13+8=21$

According to the rules of the order of arithmetic operations, we must first enclose both the multiplication and division exercises inside of parentheses:

$1+(2\times3)-(7:4)=$

We then solve the exercises within the parentheses:

$2\times3=6$

$7:4=\frac{7}{4}$

We obtain the following:

$1+6-\frac{7}{4}=$

We continue by solving the exercise from left to right:

$1+6=7$

$7-\frac{7}{4}=$

Lastly we break down the numerator of the fraction with a sum exercise as seen below:

$7-(\frac{4+3}{4})$

$7-(\frac{4}{4}+\frac{3}{4})$

$7-(1+\frac{3}{4})$

$7-1\frac{3}{4}=5\frac{1}{4}$

Let's begin by expanding the parentheses. Make sure to pay attention to the minus and plus signs, which change accordingly:

$-(-5)=5$

$8.5+(-13)=8.5-13$

We should obtain the following:

$-7+5+8.5-13=$

Now let's solve the exercise from left to right:

$-2+8.5-13=$

$6.5-13=-6.5$

Let's begin by expanding the parentheses whilst paying attention to the minus and plus signs, which change accordingly:

$+(-9.5)=-9.5$

$+(-13)=-13$

We should obtain the following:

$7.5-9.5+5-13.5=$

Now let's solve the exercise from left to right:

$-2+5-13.5=$

$3-13.5=-10.5$