Fractions do not influence the order of operations, therefore, you should treat them like any other number in the exercise.

The correct order of mathematical operations is as follows:

Question Types:

Fractions do not influence the order of operations, therefore, you should treat them like any other number in the exercise.

The correct order of mathematical operations is as follows:

Question 1

Solve the following exercise:

\( 12+3\cdot0= \)

Question 2

Solve the following exercise:

\( 2+0:3= \)

Question 3

\( \frac{25+25}{10}= \)

Question 4

\( 0:7+1= \)

Question 5

\( 12+1+0= \)

Solve the following exercise:

$12+3\cdot0=$

According to the order of operations, we first multiply and then add:

$12+(3\cdot0)=$

$3\times0=0$

$12+0=12$

$12$

Solve the following exercise:

$2+0:3=$

According to the order of operations rules, we first divide and then add:

$2+(0:3)=$

$0:3=0$

$2+0=2$

$2$

$\frac{25+25}{10}=$

Let's begin by multiplying the numerator:

$25+25=50$

We obtain the following fraction:

$\frac{50}{10}$

Finally let's reduce the numerator and denominator by 10 and we are left with the following result:

$\frac{5}{1}=5$

$5$

$0:7+1=$

According to the order of operations rules, we first divide and then add:

$0:7=0$

$0+1=1$

$1$

$12+1+0=$

According to the order of operations rules, since the exercise only involves addition operations, we will solve the problem from left to right:

$12+1=13$

$13+0=13$

13

Question 1

\( 0+0.2+0.6= \)

Question 2

\( \frac{1}{2}+0+\frac{1}{2}= \)

Question 3

\( 9-0+0.5= \)

Question 4

\( 19+1-0= \)

Question 5

\( 2+0:3= \)

$0+0.2+0.6=$

According to the order of operations rules, since the exercise only involves addition operations, we will solve the problem from left to right:

$0+0.2=0.2$

$0.2+0.6=0.8$

0.8

$\frac{1}{2}+0+\frac{1}{2}=$

According to the order of operations, since the exercise only involves addition operations, we will solve the problem from left to right:

$\frac{1}{2}+0=\frac{1}{2}$

$\frac{1}{2}+\frac{1}{2}=\frac{1}{1}=1$

$1$

$9-0+0.5=$

According to the order of operations rules, since the exercise only involves addition and subtraction, we will solve the problem from left to right:

$9-0=9$

$9+0.5=9.5$

9.5

$19+1-0=$

According to the order of operations rules, since the exercise only involves addition and subtraction operations, we will solve the problem from left to right:

$19+1=20$

$20-0=20$

$20$

$2+0:3=$

According to the order of operations rules, we first divide and then add:

$0:3=0$

$2+0=2$

$2$

Question 1

\( 12+3\times0= \)

Question 2

\( 8\times(5\times1)= \)

Question 3

\( 7\times1+\frac{1}{2}= \)

Question 4

\( \frac{6}{3}\times1= \)

Question 5

Solve:

\( 3-4+2+1 \)

$12+3\times0=$

According to the order of operations, we first multiply and then add:

$3\times0=0$

$12+0=12$

12

$8\times(5\times1)=$

According to the order of operations, we first solve the expression in parentheses:

$5\times1=5$

Now we multiply:

$8\times5=40$

40

$7\times1+\frac{1}{2}=$

According to the order of operations rules, we first insert the multiplication exercise into parentheses:

$(7\times1)+\frac{1}{2}=$

Let's solve the exercise inside the parentheses:

$7\times1=7$

And now we get the exercise:

$7+\frac{1}{2}=7\frac{1}{2}$

$7\frac{1}{2}$

$\frac{6}{3}\times1=$

According to the order of operations rules, we will solve the exercise from left to right, since there are only multiplication and division operations:

$\frac{6}{3}=2$

$2\times1=2$

$2$

Solve:

$3-4+2+1$

We will use the substitution property to arrange the exercise a bit more comfortably, we will add parentheses to the addition operation:

$(3+2+1)-4=$

We first solve the addition, from left to right:

$3+2=5$

$5+1=6$

And finally, we subtract:

$6-4=2$

2