Order or Hierarchy of Operations with Fractions - Examples, Exercises and Solutions

According to the order of operations, we first multiply and then add:

$12+(3\cdot0)=$

$3\times0=0$

$12+0=12$

According to the order of operations rules, we first divide and then add:

$2+(0:3)=$

$0:3=0$

$2+0=2$

Let's begin by multiplying the numerator:

$25+25=50$

We obtain the following fraction:

$\frac{50}{10}$

Finally let's reduce the numerator and denominator by 10 and we are left with the following result:

$\frac{5}{1}=5$

According to the order of operations rules, we first divide and then add:

$0:7=0$

$0+1=1$

According to the order of operations rules, since the exercise only involves addition operations, we will solve the problem from left to right:

$12+1=13$

$13+0=13$

According to the order of operations rules, since the exercise only involves addition operations, we will solve the problem from left to right:

$0+0.2=0.2$

$0.2+0.6=0.8$

According to the order of operations, since the exercise only involves addition operations, we will solve the problem from left to right:

$\frac{1}{2}+0=\frac{1}{2}$

$\frac{1}{2}+\frac{1}{2}=\frac{1}{1}=1$

According to the order of operations rules, since the exercise only involves addition and subtraction, we will solve the problem from left to right:

$9-0=9$

$9+0.5=9.5$

According to the order of operations rules, since the exercise only involves addition and subtraction operations, we will solve the problem from left to right:

$19+1=20$

$20-0=20$

According to the order of operations rules, we first divide and then add:

$0:3=0$

$2+0=2$

According to the order of operations, we first multiply and then add:

$3\times0=0$

$12+0=12$

According to the order of operations, we first solve the expression in parentheses:

$5\times1=5$

Now we multiply:

$8\times5=40$

According to the order of operations rules, we first insert the multiplication exercise into parentheses:

$(7\times1)+\frac{1}{2}=$

Let's solve the exercise inside the parentheses:

$7\times1=7$

And now we get the exercise:

$7+\frac{1}{2}=7\frac{1}{2}$

According to the order of operations rules, we will solve the exercise from left to right, since there are only multiplication and division operations:

$\frac{6}{3}=2$

$2\times1=2$

We will use the substitution property to arrange the exercise a bit more comfortably, we will add parentheses to the addition operation:
$(3+2+1)-4=$
We first solve the addition, from left to right:
$3+2=5$

$5+1=6$
And finally, we subtract:

$6-4=2$