Given the function:
Determine for which values of x holds
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Given the function:
Determine for which values of x holds
To solve this problem, let's break down the given quadratic function:
Since will always be greater than zero for every , the correct set of values for where is all except . Thus, the solution is expressed as:
The graph of the function below intersects the X-axis at points A and B.
The vertex of the parabola is marked at point C.
Find all values of \( x \) where \( f\left(x\right) > 0 \).
At x = 0, we get . Since we need f(x) > 0 (strictly greater than), zero doesn't count. We need values where the function is positive, not zero.
Look at the coefficient of ! Since 0.4 > 0, the parabola opens upward like a U-shape. If it were negative, it would open downward like an upside-down U.
means all real numbers except zero. This includes negative numbers like -5, positive numbers like 3.7, and even fractions like 1/2 - just not zero itself.
Graph and look where the curve is above the x-axis. You'll see it touches the x-axis only at (0,0) but is positive everywhere else!
Yes! If we had , the parabola would open downward. Then f(x) > 0 would have no solutions since the function would always be ≤ 0.
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