Solve y = 3/4x²: Finding Positive Value Domains

Question

Given the function:

y=34x2 y=\frac{3}{4}x^2

Determine for which values of x f\left(x\right) > 0 holds

Step-by-Step Solution

To determine where the function y=34x2 y = \frac{3}{4}x^2 is positive, observe:

  • **Step 1:** Identify the nature of the expression x2 x^2 .
    • The expression x2 x^2 is always non-negative for any real number x x , meaning x20 x^2 \geq 0 .
  • **Step 2:** Consider when x2 x^2 equals zero.
    • We see that x2=0 x^2 = 0 only when x=0 x = 0 , as any other value will yield a positive x2 x^2 .
  • **Step 3:** Analyze the entire function.
    • The term 34\frac{3}{4} is positive. Hence, 34x2 \frac{3}{4}x^2 becomes positive whenever x2>0 x^2 > 0 , which implies x0 x \ne 0 .
    • Therefore, for all non-zero x x , y=34x2>0 y = \frac{3}{4}x^2 > 0 .

Thus, the function y=34x2 y = \frac{3}{4}x^2 is positive for all x0 x \ne 0 .

Therefore, the correct answer is x0 x \ne 0 .

Answer

x0 x\ne0