Given the function:
y=43x2
Determine for which values of x f\left(x\right) > 0 holds
To determine where the function y=43x2 is positive, observe:
- **Step 1:** Identify the nature of the expression x2.
- The expression x2 is always non-negative for any real number x, meaning x2≥0.
- **Step 2:** Consider when x2 equals zero.
- We see that x2=0 only when x=0, as any other value will yield a positive x2.
- **Step 3:** Analyze the entire function.
- The term 43 is positive. Hence, 43x2 becomes positive whenever x2>0, which implies x=0.
- Therefore, for all non-zero x, y=43x2>0.
Thus, the function y=43x2 is positive for all x=0.
Therefore, the correct answer is x=0.