Given the function:
Determine for which values of x holds
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Given the function:
Determine for which values of x holds
To solve this problem, we're given a quadratic function . We need to determine for which values of , . Let's start by examining the function.
The given function is quadratic, and it takes the form , where . It's important to note that the coefficient is positive.
For quadratic functions in the form , where , the graph of the function is a parabola that opens upwards. This means that the values of the quadratic function are non-negative for all real . Specifically, the value is always greater than or equal to zero, reaching zero exactly when .
For the inequality to hold, would have to be negative. Since the parabola opens upwards and the vertex (the minimum point) is at , there are no real that satisfy .
Therefore, for the given function , there are no values of for which .
Thus, based on the analysis, the correct choice is that there are no values of for which holds, which is No x.
The graph of the function below intersects the X-axis at points A and B.
The vertex of the parabola is marked at point C.
Find all values of \( x \) where \( f\left(x\right) > 0 \).
Because we're squaring x! When you square any real number (positive, negative, or zero), you always get a non-negative result. Since and we multiply by positive 0.4, the result is always .
Great question! If we had , then the parabola would open downward and f(x) < 0 for all x except x = 0. The sign of the coefficient determines the parabola's direction.
No! When x = 0, we get . Since 0 is not less than 0, x = 0 doesn't satisfy the strict inequality f(x) < 0.
Look at the vertex and opening direction! For upward parabolas (a > 0), the minimum value is at the vertex. If that minimum is ≥ 0, then f(x) < 0 has no solutions. If the minimum were negative, then some x values would work.
The symbol matters! means strictly less than zero, so f(x) = 0 doesn't count. But includes zero, so x = 0 would be a solution for the ≤ version.
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