Given the function:
Determine for which values of x holds
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Given the function:
Determine for which values of x holds
To solve this problem, we're given a quadratic function . We need to determine for which values of , . Let's start by examining the function.
The given function is quadratic, and it takes the form , where . It's important to note that the coefficient is positive.
For quadratic functions in the form , where , the graph of the function is a parabola that opens upwards. This means that the values of the quadratic function are non-negative for all real . Specifically, the value is always greater than or equal to zero, reaching zero exactly when .
For the inequality to hold, would have to be negative. Since the parabola opens upwards and the vertex (the minimum point) is at , there are no real that satisfy .
Therefore, for the given function , there are no values of for which .
Thus, based on the analysis, the correct choice is that there are no values of for which holds, which is No x.
The graph of the function below does not intersect the \( x \)-axis.
The parabola's vertex is marked A.
Find all values of \( x \) where
\( f\left(x\right) > 0 \).
Because we're squaring x! When you square any real number (positive, negative, or zero), you always get a non-negative result. Since and we multiply by positive 0.4, the result is always .
Great question! If we had , then the parabola would open downward and f(x) < 0 for all x except x = 0. The sign of the coefficient determines the parabola's direction.
No! When x = 0, we get . Since 0 is not less than 0, x = 0 doesn't satisfy the strict inequality f(x) < 0.
Look at the vertex and opening direction! For upward parabolas (a > 0), the minimum value is at the vertex. If that minimum is ≥ 0, then f(x) < 0 has no solutions. If the minimum were negative, then some x values would work.
The symbol matters! means strictly less than zero, so f(x) = 0 doesn't count. But includes zero, so x = 0 would be a solution for the ≤ version.
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