Addition: Addition of 2-digit and 2-digit numbers with the regrouping of tens and ones

To solve this problem, we will use straightforward addition:

• Step 1: Identify the numbers to be added. We have 28 blocks and add 36 blocks.
• Step 2: Set up the addition equation: $28 + 36$.
• Step 3: Perform the addition: $28 + 36 = 64$.

Therefore, the total number of blocks is $64$.

To solve this problem, we need to find the total number of blocks after adding 19 blocks to an existing 45 blocks.

Step 1: Identify the numbers involved:

• Initial number of blocks: $45$
• Additional blocks: $19$

Step 2: Perform the addition calculation: $45 + 19 = 64$

Now, let's explain the addition in detail:

• Start by adding the ones place digits: $5 + 9 = 14$. Write down 4 and carry over 1 to the tens place.
• Next, add the tens place digits, along with the carry-over: $4 + 1 (carry) + 1 = 6$.

Thus, the total number of blocks is $64$.

The correct answer choice is: 4

Therefore, the solution to the problem is $64$.

To solve this problem, we will add the numbers by employing the method of columnar addition:

• Step 1: Add the units (rightmost digits) of both numbers:
  Given units: $3$ (from 53) and $8$ (from 28).
• Calculate: $3 + 8 = 11$. Since this is more than 10, we write down $1$ in the units place and carry over $1$ to the tens place.
• Step 2: Add the tens (leftmost digits) of both numbers:
  Given tens: $5$ (from 53) and $2$ (from 28).
• Including the carry-over: $5 + 2 + 1 = 8$.
• Place $8$ in the tens place.

Therefore, the resulting number after adding 53 and 28 is $81$.

To solve this problem, we'll follow these steps:

• Step 1: Align the numbers vertically by place value.

• Step 2: Add the ones place digits and handle any carrying over if necessary.

• Step 3: Add the tens place digits, including any carried over value.

Let's work through each step:
Step 1: Write the numbers 65 and 27 one below the other:

$\begin{aligned} & 65 \\ + & 27 \\ \end{aligned}$

Step 2: Starting with the ones place, add 5 and 7 to get 12. Write down 2 and carry over 1 to the tens place.
Step 3: In the tens place, add 6 and 2, plus the carried over 1, giving a total of 9.

The calculation results in:

$\begin{aligned} & 65 \\ + & 27 \\ &\over92 \\ \end{aligned}$

Therefore, the total number of blocks is $92$.

To solve this problem, let's begin by stating the numbers involved in the addition:
- We start with an initial number of blocks: $17$.
- Then, we add an additional number of blocks: $25$.

We need to find the sum of these two numbers to determine the total number of blocks:

• $17 + 25$

Let's compute the sum:
To find $17 + 25$, we can add the numbers directly:

• First, add the ones place: $7 + 5 = 12$, which gives us 2 in the ones place and carry over 1 to the tens place.
• Then, add the tens place numbers: $1 + 2 + 1 = 4$.

This calculation results in the total number of blocks being $42$.

Therefore, the correct answer to the problem is $42$.