Addition: Graphical representation

To solve this problem, we need to add one ten (10) and one unit (1) to the number 66.

We'll follow these steps to find the new number:

• Step 1: Start with the original number, $66$.
• Step 2: Add one ten. This means adding $10$ to $66$.
  $66 + 10 = 76$.
• Step 3: Add one unit to the result from Step 2. This means adding $1$ to $76$.
  $76 + 1 = 77$.

Therefore, after adding one ten and one unit to 66, the resulting number is $77$.

To find the resulting number when ten units are added to 72, we will perform the following steps:

• Step 1: Identify the starting number, which is 72.
• Step 2: Add 10 to the starting number. This is done by calculating $72 + 10$.

Let's perform the calculation:

$72 + 10 = 82$

Therefore, the resulting number when ten units are added to 72 is $82$.

To solve this problem, we'll perform simple addition:
Step 1: Identify the numbers to be added, which are 31 and 50.
Step 2: Calculate the sum: $31 + 50$.

Let's perform the calculation:

• Start the addition from the rightmost digit (units place).
• In the units place, add 1 (from 31) and 0 (from 50), giving us 1.
• In the tens place, add 3 (from 31) and 5 (from 50), which gives us 8.

Since there's nothing to carry over, the sum directly gives us the resulting number. Thus, $31 + 50 = 81$.

Therefore, the resulting number when adding fifty units to the number 31 is $81$.

To solve this problem, we'll perform the addition step-by-step, carefully keeping track of place values.

First, we start with the number 34.
We need to add 2 tens, which is equivalent to adding 20. Thus:
$34 + 20 = 54$

Next, add 2 units to the new total:
$54 + 2 = 56$

The final number we get after adding 2 tens and 2 units to 34 is $\mathbf{56}$.

To solve this problem, we'll follow these steps:

• Step 1: Add the 3 tens to the number 55.
• Step 2: Add the 4 units to the result from Step 1.

Let's work through each step:

Step 1: We need to add three tens to 55. Three tens equal $3 \times 10 = 30$.
Thus, adding 30 to 55 gives us:

$55 + 30 = 85$

Step 2: Now, we add the 4 units to the result of Step 1 (which is 85).
Adding 4 gives us:

$85 + 4 = 89$

Therefore, the solution to the problem is $89$.

To solve this problem, we'll follow these steps:

• Step 1: Identify the initial number.
• Step 2: Add 3 tens to the initial number.
• Step 3: Add 4 units to the result of Step 2.

Now, let's work through each step:
Step 1: The problem gives us the initial number as $61$.
Step 2: Add 3 tens (which is $30$) to $61$:
$61 + 30 = 91$.
Step 3: Add 4 units to $91$:
$91 + 4 = 95$.

Therefore, the resulting number after adding 3 tens and 4 units to $61$ is $95$.

To solve the problem, we will perform simple addition:

• Step 1: Identify the numbers involved. We have the number $44$ and we need to add $30$ to it.
• Step 2: Use the addition formula to find the sum. This is calculated as $44 + 30$.
• Step 3: Perform the calculation. Since $44 + 30 = 74$, we find that the resulting number is $74$.

Therefore, the solution to the problem is $74$.

To solve this problem, we'll follow these steps:

• Step 1: Identify the initial number and the amount to be added.
• Step 2: Perform the addition of the two numbers.

Now, let's work through each step:

Step 1: The initial number is given as 66, and we need to add 20 to it.

Step 2: We'll perform the addition:
$66 + 20 = 86$

Therefore, the solution to the problem is $86$.

To solve this problem, we'll follow these steps:

• Step 1: Calculate the value of 6 tens.
• Step 2: Calculate the value of 7 units.
• Step 3: Add the values obtained in Steps 1 and 2.
• Step 4: Add this result to the initial number.

Let's work through each step:

Step 1: Calculate the value of 6 tens.
Each "ten" represents 10 units, so 6 tens equals $6 \times 10 = 60$.

Step 2: Calculate the value of 7 units.
Each "unit" represents 1, so 7 units equal $7 \times 1 = 7$.

Step 3: Add the values from Steps 1 and 2.
The total value of tens and units is $60 + 7 = 67$.

Step 4: Add this result to the initial number, 12.
So, $12 + 67 = 79$.

Therefore, when we add 6 tens and 7 units to the number 12, we obtain $79$.

To solve this problem, we will add the numbers by employing the method of columnar addition:

• Step 1: Add the units (rightmost digits) of both numbers:
  Given units: $3$ (from 53) and $8$ (from 28).
• Calculate: $3 + 8 = 11$. Since this is more than 10, we write down $1$ in the units place and carry over $1$ to the tens place.
• Step 2: Add the tens (leftmost digits) of both numbers:
  Given tens: $5$ (from 53) and $2$ (from 28).
• Including the carry-over: $5 + 2 + 1 = 8$.
• Place $8$ in the tens place.

Therefore, the resulting number after adding 53 and 28 is $81$.

To solve this problem, we need to add the additional blocks to the existing blocks:

• Step 1: Start with the initial number of blocks, which is 63.
• Step 2: Add the additional blocks, which are 9, using the addition operation.
• Step 3: Perform the addition: $63 + 9$.

Now, let's calculate:

Performing the addition, we have:

This calculation gives us the total number of blocks. Therefore, the solution to the problem is that there are 72 blocks in total.

To solve this problem, let's follow the steps:

• Step 1: Identify the numbers that need to be added. In this case, they are $4$ and $8$.
• Step 2: Apply the addition operation to those numbers: $4 + 8$.
• Step 3: Perform the calculation. Adding those numbers gives us: $4 + 8 = 12$.

Therefore, the total number of units when we add 4 units to 8 units is $\mathbf{12}$.

To solve this problem, follow these steps:

• Step 1: Identify Given Information: We have 57 blocks initially.
• Step 2: Apply Addition: We will add 8 blocks to the initial 57 blocks.
• Step 3: Perform Calculation: Calculate the sum using addition.

Now, carrying out the calculation:
We start with $57$ blocks. When we add another $8$ blocks, the operation is:
$57 + 8 = 65$

Therefore, after adding the additional blocks, we have a total of $65$ blocks.

To solve this problem, we'll follow these steps:

• Step 1: Align the numbers vertically by place value.

• Step 2: Add the ones place digits and handle any carrying over if necessary.

• Step 3: Add the tens place digits, including any carried over value.

Let's work through each step:
Step 1: Write the numbers 65 and 27 one below the other:

$\begin{aligned} & 65 \\ + & 27 \\ \end{aligned}$

Step 2: Starting with the ones place, add 5 and 7 to get 12. Write down 2 and carry over 1 to the tens place.
Step 3: In the tens place, add 6 and 2, plus the carried over 1, giving a total of 9.

The calculation results in:

$\begin{aligned} & 65 \\ + & 27 \\ &\over92 \\ \end{aligned}$

Therefore, the total number of blocks is $92$.

To solve this problem, we will use straightforward addition:

• Step 1: Identify the numbers to be added. We have 28 blocks and add 36 blocks.
• Step 2: Set up the addition equation: $28 + 36$.
• Step 3: Perform the addition: $28 + 36 = 64$.

Therefore, the total number of blocks is $64$.

To solve this problem, let's begin by stating the numbers involved in the addition:
- We start with an initial number of blocks: $17$.
- Then, we add an additional number of blocks: $25$.

We need to find the sum of these two numbers to determine the total number of blocks:

• $17 + 25$

Let's compute the sum:
To find $17 + 25$, we can add the numbers directly:

• First, add the ones place: $7 + 5 = 12$, which gives us 2 in the ones place and carry over 1 to the tens place.
• Then, add the tens place numbers: $1 + 2 + 1 = 4$.

This calculation results in the total number of blocks being $42$.

Therefore, the correct answer to the problem is $42$.

To solve this problem, we will follow these steps:

• Step 1: Identify the numbers given in the problem.
• Step 2: Use addition to find the sum of these numbers.
• Step 3: Verify that the sum corresponds to one of the answer choices.

Now, let's work through each step:
Step 1: The problem gives us 3 units and 9 units.
Step 2: We'll use the addition operation.
$3 + 9 = 12$
Step 3: Check the given choices to ensure our answer, 12, matches one of them.

Therefore, the solution to the problem is $12$.

To solve this problem, we need to find the total number of blocks after adding 19 blocks to an existing 45 blocks.

Step 1: Identify the numbers involved:

• Initial number of blocks: $45$
• Additional blocks: $19$

Step 2: Perform the addition calculation: $45 + 19 = 64$

Now, let's explain the addition in detail:

• Start by adding the ones place digits: $5 + 9 = 14$. Write down 4 and carry over 1 to the tens place.
• Next, add the tens place digits, along with the carry-over: $4 + 1 (carry) + 1 = 6$.

Thus, the total number of blocks is $64$.

The correct answer choice is: 4

Therefore, the solution to the problem is $64$.

To determine the total number of blocks, we need to add the initial quantity of blocks to the additional blocks. Here's how you can calculate it step by step:

• Step 1: Identify the initial number of blocks, which is 88.
• Step 2: Identify the number of additional blocks being added, which is 6.
• Step 3: Perform the addition: $88 + 6$.

Now, let's perform the addition:

$88 + 6 = 94$

Therefore, the total number of blocks after adding 88 and 6 is $94$.

To solve this problem, we'll follow these steps:

• Identify the two numbers to be added: 5 and 6.
• Add these two numbers together using basic arithmetic.

Let's work through the solution step-by-step:
We need to calculate $5 + 6$. The operation involves simple addition:
$5 + 6 = 11$

Therefore, the result is $11 \text{ units}$.

Considering the provided multiple-choice answers, we check:

• corresponds to

  $11 \text{ units}$

The correct choice is Option 3.