Arithmetic Sequence Analysis: Does 28 Belong in 51,47,43,39...?

Question

Assuming that the series continues with the same legality, does the number 28 28 Is it part of the series?

51,47,43,39 51,47,43,39\ldots

Video Solution

Solution Steps

00:00 Is 28 a member of the sequence?
00:03 This is the sequence formula
00:07 Let's substitute in the formula and solve for X
00:10 If the solution for X is whole and positive, then it's a member of the sequence
00:16 Let's isolate X
00:40 The solution for X is positive but not whole, therefore not a member
00:47 And this is the solution to the question

Step-by-Step Solution

To solve this problem, follow these steps:

  • Step 1: Identify the given information in the arithmetic sequence.
  • Step 2: Set up the formula for the nth term of an arithmetic sequence.
  • Step 3: Solve for n n and check if it's a natural number.

Now, let's work through each step:
Step 1: The first term a1=51 a_1 = 51 , and the common difference d=4 d = -4 .

Step 2: The formula for the nth term an a_n of an arithmetic sequence is:

an=a1+(n1)d a_n = a_1 + (n-1) \cdot d

Substituting the known values to find if 28 is an element of this series:

28=51+(n1)(4) 28 = 51 + (n-1) \cdot (-4)

Step 3: Simplify and solve for n n :

28=514(n1) 28 = 51 - 4(n-1)

28=514n+4 28 = 51 - 4n + 4

28=554n 28 = 55 - 4n

4n=5528 4n = 55 - 28

4n=27 4n = 27

n=274=6.75 n = \frac{27}{4} = 6.75

Since n n must be a natural number (a positive integer) to indicate a position in the sequence, and 6.75 is not a natural number, we conclude that 28 is not part of the sequence.

Therefore, the solution to the problem is No.

Answer

No