Verify if 21 Belongs to the Arithmetic Sequence: 51, 47, 43, 39,...

Question

Assuming that the series continues with the same legality, does the number 21 21 Is it part of the series?

51,47,43,39 51,47,43,39\ldots

Video Solution

Solution Steps

00:00 Is 21 a member of the sequence?
00:03 This is the sequence formula
00:08 Let's substitute in the formula and solve for X
00:13 If the solution for X is whole and positive, then it's a member of the sequence
00:19 Let's isolate X
00:45 The solution for X is positive but not whole, therefore not a member
00:48 And this is the solution to the question

Step-by-Step Solution

To determine if the number 21 21 is part of the given arithmetic sequence 51,47,43,39, 51, 47, 43, 39, \ldots , we'll follow these steps:

  • Step 1: Identify the common difference.
  • Step 2: Use the arithmetic sequence formula to check if 21 21 is a term.

Step 1: Calculate the common difference, d d .
The difference between consecutive terms is 5147=4 51 - 47 = 4 , 4743=4 47 - 43 = 4 , 4339=4 43 - 39 = 4 . So, the common difference d=4 d = -4 .

Step 2: Use the formula for the n n -th term of an arithmetic sequence:

an=a1+(n1)d a_n = a_1 + (n-1) \cdot d

Substitute the known values where a1=51 a_1 = 51 and d=4 d = -4 :

21=51+(n1)(4) 21 = 51 + (n-1)(-4)

Simplify and solve for n n :

21=514n+4 21 = 51 - 4n + 4

21=554n 21 = 55 - 4n

4n=5521 4n = 55 - 21

4n=34 4n = 34

n=344 n = \frac{34}{4}

n=8.5 n = 8.5

Since n n is not an integer, 21 21 is not a term in the sequence.

Therefore, the answer is No.

Answer

No