The series describes the price of a meal in a food chain from January to December.
How much does food cost in December?
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The series describes the price of a meal in a food chain from January to December.
How much does food cost in December?
To solve this problem, we'll follow these steps:
Now, let's work through each step:
Step 1: Common Difference Calculation:
Observe the pattern from January () to July ().
Calculate the common difference: .
This confirms each month increases by .
Step 2: Find the Price for December:
Starting from July ():
63
Is there a term-to-term rule for the sequence below?
18 , 22 , 26 , 30
Check if the difference between consecutive terms is constant. Here: 33-30=3, 36-33=3, 39-36=3. Since all differences equal 3, it's arithmetic!
Absolutely! Use \( a_n = a_1 + (n-1)d \) where a₁ = 30, d = 3, and n = 12 for December: \( a_{12} = 30 + (12-1)(3) = 63 \)
Double-check by working backwards! Start from your December answer and subtract 3 repeatedly to see if you get back to July's price of 48.
This tests your understanding of arithmetic sequences. The given values establish the pattern, and you use that pattern to find the missing December value.
The consistent difference of \( +3 \) each month clearly shows it's arithmetic, not geometric or quadratic. Always verify the pattern type before solving!
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