In a classroom there are 10 chairs numbered according to the constant property. Complete the series of chairs:
20 , 18
16 , 14
_ , _
8 , 6
4 , 2
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In a classroom there are 10 chairs numbered according to the constant property. Complete the series of chairs:
20 , 18
16 , 14
_ , _
8 , 6
4 , 2
To solve this problem, we'll follow these steps:
Now, let's work through each step:
Step 1: The sequence provided is 20, 18, 16, 14, __, __, 8, 6, 4, 2.
We notice that each number differs from the previous one by (20 to 18, 18 to 16, etc.). This suggests an arithmetic sequence with a common difference of .
Step 2: Let's continue this pattern to find the missing numbers. We have 16, 14, and then the blank spaces before reaching 8. So, following the pattern:
From 14, subtract 2 to get 12.
From 12, subtract 2 to get 10.
So, the missing numbers in the sequence are 12 and 10.
Step 3: Verify the sequence by checking the pattern:
Starting from 20: 20, 18, 16, 14, 12, 10, 8, 6, 4, 2.
Each step follows the pattern of subtracting 2.
Therefore, the missing numbers in the series are .
12 , 10
12 ☐ 10 ☐ 8 7 6 5 4 3 2 1
Which numbers are missing from the sequence so that the sequence has a term-to-term rule?
Look at the first few terms! In this problem, 20 becomes 18, then 16 - the numbers are getting smaller. This means we have a decreasing arithmetic sequence with a negative common difference.
Find the difference between consecutive terms. Here: 18 - 20 = -2, and 16 - 18 = -2. When the difference is the same each time, you have an arithmetic sequence!
That would break the pattern! If we had 14, 15, 13, 8, the differences would be - not constant. In arithmetic sequences, the difference must stay the same.
Write out the complete sequence with your answers: 20, 18, 16, 14, 12, 10, 8, 6, 4, 2. Each number should be exactly 2 less than the previous one!
Yes! If the common difference is positive, the sequence increases. If it's negative (like here), the sequence decreases. Both are perfectly valid arithmetic sequences.
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