Calculate (1/3)³: Solving the Cube of One-Third

Fractional Exponents with Cube Powers

(13)3= (\frac{1}{3})^3=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Solve
00:05 Let's break down the exponent into multiplications
00:12 Make sure to multiply numerator by numerator and denominator by denominator
00:16 Calculate the multiplications
00:21 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

(13)3= (\frac{1}{3})^3=

2

Step-by-step solution

To solve the expression (13)3 \left(\frac{1}{3}\right)^3 , we will apply the power of a fraction rule.

Step 1: Begin with the expression (13)3 \left(\frac{1}{3}\right)^3 .
This means we need to calculate 1333 \frac{1^3}{3^3} .

Step 2: Evaluate 13 1^3 and 33 3^3 :
- 13=1×1×1=1 1^3 = 1 \times 1 \times 1 = 1
- 33=3×3×3=27 3^3 = 3 \times 3 \times 3 = 27

Step 3: Construct the fraction with these powers:
1333=127 \frac{1^3}{3^3} = \frac{1}{27} .

Therefore, the value of (13)3 \left(\frac{1}{3}\right)^3 is 127\frac{1}{27}.

3

Final Answer

127 \frac{1}{27}

Key Points to Remember

Essential concepts to master this topic
  • Power Rule: When raising a fraction to a power, apply to numerator and denominator
  • Technique: (13)3=1333=127 (\frac{1}{3})^3 = \frac{1^3}{3^3} = \frac{1}{27}
  • Check: Verify by multiplying: 127×27=1 \frac{1}{27} \times 27 = 1 when cubed gives original fraction ✓

Common Mistakes

Avoid these frequent errors
  • Only applying the exponent to the numerator
    Don't just calculate 13 1^3 and leave 3 unchanged = 13 \frac{1}{3} ! This ignores the power rule for fractions and gives the original fraction instead of its cube. Always apply the exponent to both numerator AND denominator separately.

Practice Quiz

Test your knowledge with interactive questions

\( 11^2= \)

FAQ

Everything you need to know about this question

Why does cubing a unit fraction make it smaller?

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When you cube a fraction less than 1, like 13 \frac{1}{3} , you're multiplying it by itself three times. Since you're multiplying by numbers less than 1, the result gets smaller: 13×13×13=127 \frac{1}{3} \times \frac{1}{3} \times \frac{1}{3} = \frac{1}{27} .

How is this different from 133 \frac{1^3}{3} ?

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That's completely different! 133=13 \frac{1^3}{3} = \frac{1}{3} means only the numerator is cubed. But (13)3 (\frac{1}{3})^3 means the entire fraction is cubed, so both parts get the exponent: 1333 \frac{1^3}{3^3} .

Can I just multiply 13×13×13 \frac{1}{3} \times \frac{1}{3} \times \frac{1}{3} ?

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Absolutely! That's exactly what cubing means. Multiply the numerators: 1×1×1=1 1 \times 1 \times 1 = 1 , and multiply the denominators: 3×3×3=27 3 \times 3 \times 3 = 27 to get 127 \frac{1}{27} .

What if the numerator wasn't 1?

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The same rule applies! For example, (25)3=2353=8125 (\frac{2}{5})^3 = \frac{2^3}{5^3} = \frac{8}{125} . Always cube both the top and bottom numbers separately.

How do I remember this rule?

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Think of it as distributing the exponent: the exponent outside the parentheses applies to everything inside. Just like (ab)3=a3b3 (ab)^3 = a^3b^3 , we have (ab)3=a3b3 (\frac{a}{b})^3 = \frac{a^3}{b^3} !

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