Calculate (2×8×7)²: Square of Triple Product Problem

Power of Products with Multiple Terms

(2×8×7)2= (2\times8\times7)^2=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:06 Alright everyone, let's dive in!
00:09 We'll explore two ways to solve this problem.
00:13 First up, we'll calculate each multiplication by itself. Then, we'll raise the result to the power. Let's see how it goes.
00:32 That's one way to solve it!
00:35 Now, let's try the second method using a special formula.
00:39 When we multiply numbers and raise them to a power, we can break it down.
00:44 Each number gets its own power, making it simpler.
00:49 Let's apply this formula in our task.
00:52 We'll remove the parentheses and raise each part to its power.
00:57 Next, calculate each individual power.
01:01 Finally, multiply the results together.
01:04 And there we go! That's how we solve this problem. Great job!

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

(2×8×7)2= (2\times8\times7)^2=

2

Step-by-step solution

We begin by using the power rule for parentheses:

(zt)n=zntn (z\cdot t)^n=z^n\cdot t^n

That is, the power applied to a product inside parentheses, is applied to each of the terms within, when the parentheses are opened.

We then apply the above rule to the problem:

(287)2=228272 (2\cdot8\cdot7)^2=2^2\cdot8^2\cdot7^2

Therefore, the correct answer is option d.

Note:

From the formula of the power property inside parentheses mentioned above, it might seem as though it refers to only two terms of the product inside of the parentheses, but in reality, it is also valid for the power over a multiplication of many terms inside parentheses, as was seen above.

A good exercise is to demonstrate that if the previous property is valid for a power over a product of two terms inside parentheses (as formulated above), then it is also valid for a power over several terms of the product inside parentheses (for example - three terms, etc.).

3

Final Answer

228272 2^2\cdot8^2\cdot7^2

Key Points to Remember

Essential concepts to master this topic
  • Power Rule: Apply exponent to each factor inside parentheses
  • Technique: (287)2=228272 (2\cdot8\cdot7)^2 = 2^2\cdot8^2\cdot7^2 distributes the exponent
  • Check: Calculate both ways: (112)2=12544 (112)^2 = 12544 and 46449=12544 4\cdot64\cdot49 = 12544

Common Mistakes

Avoid these frequent errors
  • Only squaring one term while leaving others unchanged
    Don't square just the first term like 22×8×7=4×56=224 2^2\times8\times7 = 4\times56 = 224 ! This ignores the power rule and gives a completely wrong result. Always apply the exponent to every single factor inside the parentheses: 228272 2^2\cdot8^2\cdot7^2 .

Practice Quiz

Test your knowledge with interactive questions

\( 112^0=\text{?} \)

FAQ

Everything you need to know about this question

Why can't I just calculate 2×8×7 first and then square it?

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You absolutely can do that! Both methods work: calculate 2×8×7=112 2\times8\times7 = 112 , then 1122=12544 112^2 = 12544 . The power rule 228272 2^2\cdot8^2\cdot7^2 is just another valid approach.

Does the power rule work with more than 3 numbers?

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Yes! The rule (abcd)n=anbncndn (a\cdot b\cdot c\cdot d)^n = a^n\cdot b^n\cdot c^n\cdot d^n works for any number of factors. Just apply the exponent to each factor inside the parentheses.

What if the numbers were different, like (3×5×4)²?

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Same process! (3×5×4)2=325242=92516 (3\times5\times4)^2 = 3^2\cdot5^2\cdot4^2 = 9\cdot25\cdot16 . The power rule works with any numbers inside the parentheses.

Is 2²×8×7 completely wrong?

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Yes, it's wrong! This only squares the first number. The correct answer requires squaring all three numbers: 228272 2^2\cdot8^2\cdot7^2 .

How can I remember this power rule?

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Think: "The power outside affects everyone inside!" Just like distributing multiplication, you distribute the exponent to every factor in the parentheses.

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