Calculate Ascending Area: Finding Area Under f(x)=2x²

Question

Find the ascending area of the function

f(x)=2x2 f(x)=2x^2

Video Solution

Solution Steps

00:00 Find the domain of increase of the function
00:04 We'll examine the coefficient of X squared, it's positive so the function is happy
00:08 We'll examine the trinomial coefficients
00:16 We'll use the formula to find the vertex of the parabola
00:21 We'll substitute appropriate values according to the given data and solve to find the vertex
00:27 This is the X value at the vertex of the parabola
00:32 We'll determine based on the type of parabola when it's decreasing and when it's increasing
00:37 We'll draw the X-axis and find the domain of increase
00:41 And this is the solution to the question

Step-by-Step Solution

To determine the intervals where the function f(x)=2x2 f(x) = 2x^2 is increasing, we will analyze the derivative of the function:

Step 1: Differentiate the function.
The derivative of f(x)=2x2 f(x) = 2x^2 is f(x)=4x f'(x) = 4x .

Step 2: Determine where f(x)>0 f'(x) > 0 .
To find the increasing intervals, set 4x>0 4x > 0 . Solving this inequality, we obtain x>0 x > 0 .

Therefore, the function f(x)=2x2 f(x) = 2x^2 is increasing for x>0 x > 0 .

Consequently, the correct answer is the interval where the function is increasing, which is 0<x 0 < x .

Answer

0 < x