Calculate Descending Area of f(x)=2x-x²+1: Quadratic Function Analysis

Question

Find the descending area of the function

f(x)=2xx2+1 f(x)=2x-x^2+1

Video Solution

Step-by-Step Solution

To determine where the function f(x)=2xx2+1 f(x) = 2x - x^2 + 1 is decreasing, we follow these steps:

  • Step 1: Find the derivative
    The derivative of the function f(x)=2xx2+1 f(x) = 2x - x^2 + 1 is found using standard calculus rules. Thus, f(x)=ddx(2xx2+1)=22x f'(x) = \frac{d}{dx}(2x - x^2 + 1) = 2 - 2x .
  • Step 2: Determine where the derivative is negative
    Set the derivative 22x 2 - 2x less than zero to find where the function is decreasing:

22x<0 2 - 2x < 0

Solve for x x :
Subtract 2 from both sides to get:

2x<2 -2x < -2

Now, divide both sides by -2, remembering to reverse the inequality sign:

x>1 x > 1

Conclusion: The function f(x)=2xx2+1 f(x) = 2x - x^2 + 1 is decreasing for x>1 x > 1 . Thus, the descending area is represented by the interval 1<x 1 < x .

The correct choice that matches this interval is:

1<x 1 < x

Answer

1 < x