Calculate Cuboid Dimensions: Finding Length of 4x3 Rectangles and 4x4 Squares Construction

Surface Area Analysis with Geometric Feasibility

What are the dimensions of a cuboid composed of two 4X3 rectangles

and of four 4X4 squares?

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Step-by-step written solution

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1

Understand the problem

What are the dimensions of a cuboid composed of two 4X3 rectangles

and of four 4X4 squares?

2

Step-by-step solution

To determine the feasability of a cuboid composed of two 4x3 rectangles and four 4x4 squares, we start by calculating the total surface area these would provide:

The total surface area contributes as follows:
- Two 4x3 rectangles: 2×4×3=242 \times 4 \times 3 = 24
- Four 4x4 squares: 4×4×4=644 \times 4 \times 4 = 64

The total surface area is 24+64=8824 + 64 = 88.

When forming a cuboid with dimensions l×w×hl \times w \times h, the surface area should satisfy:
2(lw+lh+wh)=882(lw + lh + wh) = 88.

Now, let us examine possible dimensions that can result from the given face dimensions:

  • Dimension 1: 4 (from the squares).
  • Dimension 2: 3 (from the rectangles).
  • Dimension 3 needs consideration from remaining panels.

Since using the given two 4x3 rectangles and four 4x4 squares in a valid arrangement providing 6 surface faces does not meet the criteria without repeating or extending beyond six faces, the random assembly of these square and rectangular panels cannot result in a valid orthogonal shape (cuboid).

Conclusively, this orthohedron is not possible.

Thus, the solution is that 'This orthohedron is not possible.'

3

Final Answer

This orthohedron is not possible.

Key Points to Remember

Essential concepts to master this topic
  • Surface Area Rule: A cuboid has exactly 6 faces with total area 2(lw+lh+wh)2(lw + lh + wh)
  • Face Matching: Calculate total given area: 2(12)+4(16)=882(12) + 4(16) = 88 square units
  • Feasibility Check: Verify if 6 faces can form valid cuboid dimensions ✓

Common Mistakes

Avoid these frequent errors
  • Assuming all given faces can always form a valid cuboid
    Don't just add up the areas and assume they'll work = impossible shapes! Just because you have rectangular and square faces doesn't mean they can connect properly. Always check if the dimensions can actually form a closed 3D shape with exactly 6 faces.

Practice Quiz

Test your knowledge with interactive questions

A cuboid is shown below:

222333555

What is the surface area of the cuboid?

FAQ

Everything you need to know about this question

Why can't I just arrange these faces into any cuboid?

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A cuboid needs exactly 6 faces where opposite faces are identical. With two 4×3 rectangles and four 4×4 squares, you have the right number of faces, but they must match the specific dimensions of a valid cuboid.

How do I know if the dimensions work together?

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For a cuboid with dimensions l×w×hl \times w \times h, you need three pairs of identical opposite faces. Check if your given faces can form these three pairs with consistent edge lengths.

What does 'orthohedron not possible' mean?

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An orthohedron is just another name for a rectangular prism or cuboid. 'Not possible' means these specific faces cannot be arranged to form a valid 3D rectangular shape.

Can I have leftover faces when building a cuboid?

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No! A cuboid must use exactly 6 faces - no more, no less. If your given faces can't form exactly 6 faces of a cuboid, then it's impossible.

How do I calculate the total surface area correctly?

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Multiply each face's area by how many times it appears:

  • Two 4×3 rectangles: 2×12=242 \times 12 = 24
  • Four 4×4 squares: 4×16=644 \times 16 = 64
  • Total: 24+64=8824 + 64 = 88

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