Calculate Cuboid Dimensions: Finding Length of 4x3 Rectangles and 4x4 Squares Construction

Question

What are the dimensions of a cuboid composed of two 4X3 rectangles

and of four 4X4 squares?

Step-by-Step Solution

To determine the feasability of a cuboid composed of two 4x3 rectangles and four 4x4 squares, we start by calculating the total surface area these would provide:

The total surface area contributes as follows:
- Two 4x3 rectangles: 2×4×3=242 \times 4 \times 3 = 24
- Four 4x4 squares: 4×4×4=644 \times 4 \times 4 = 64

The total surface area is 24+64=8824 + 64 = 88.

When forming a cuboid with dimensions l×w×hl \times w \times h, the surface area should satisfy:
2(lw+lh+wh)=882(lw + lh + wh) = 88.

Now, let us examine possible dimensions that can result from the given face dimensions:

  • Dimension 1: 4 (from the squares).
  • Dimension 2: 3 (from the rectangles).
  • Dimension 3 needs consideration from remaining panels.

Since using the given two 4x3 rectangles and four 4x4 squares in a valid arrangement providing 6 surface faces does not meet the criteria without repeating or extending beyond six faces, the random assembly of these square and rectangular panels cannot result in a valid orthogonal shape (cuboid).

Conclusively, this orthohedron is not possible.

Thus, the solution is that 'This orthohedron is not possible.'

Answer

This orthohedron is not possible.