What are the dimensions of a cuboid composed of two 4X3 rectangles
and of four 4X4 squares?
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What are the dimensions of a cuboid composed of two 4X3 rectangles
and of four 4X4 squares?
To determine the feasability of a cuboid composed of two 4x3 rectangles and four 4x4 squares, we start by calculating the total surface area these would provide:
The total surface area contributes as follows:
- Two 4x3 rectangles: 
- Four 4x4 squares: 
The total surface area is .
When forming a cuboid with dimensions , the surface area should satisfy:
.
Now, let us examine possible dimensions that can result from the given face dimensions:
Since using the given two 4x3 rectangles and four 4x4 squares in a valid arrangement providing 6 surface faces does not meet the criteria without repeating or extending beyond six faces, the random assembly of these square and rectangular panels cannot result in a valid orthogonal shape (cuboid).
Conclusively, this orthohedron is not possible.
Thus, the solution is that 'This orthohedron is not possible.'
This orthohedron is not possible.
A cuboid is shown below:
What is the surface area of the cuboid?
A cuboid needs exactly 6 faces where opposite faces are identical. With two 4×3 rectangles and four 4×4 squares, you have the right number of faces, but they must match the specific dimensions of a valid cuboid.
For a cuboid with dimensions , you need three pairs of identical opposite faces. Check if your given faces can form these three pairs with consistent edge lengths.
An orthohedron is just another name for a rectangular prism or cuboid. 'Not possible' means these specific faces cannot be arranged to form a valid 3D rectangular shape.
No! A cuboid must use exactly 6 faces - no more, no less. If your given faces can't form exactly 6 faces of a cuboid, then it's impossible.
Multiply each face's area by how many times it appears:
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