What are the dimensions of a cuboid composed of two 4X3 rectangles
and of four 4X4 squares?
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What are the dimensions of a cuboid composed of two 4X3 rectangles
and of four 4X4 squares?
To determine the feasability of a cuboid composed of two 4x3 rectangles and four 4x4 squares, we start by calculating the total surface area these would provide:
The total surface area contributes as follows:
- Two 4x3 rectangles:
- Four 4x4 squares:
The total surface area is .
When forming a cuboid with dimensions , the surface area should satisfy:
.
Now, let us examine possible dimensions that can result from the given face dimensions:
Since using the given two 4x3 rectangles and four 4x4 squares in a valid arrangement providing 6 surface faces does not meet the criteria without repeating or extending beyond six faces, the random assembly of these square and rectangular panels cannot result in a valid orthogonal shape (cuboid).
Conclusively, this orthohedron is not possible.
Thus, the solution is that 'This orthohedron is not possible.'
This orthohedron is not possible.
Identify the correct 2D pattern of the given cuboid:
A cuboid needs exactly 6 faces where opposite faces are identical. With two 4×3 rectangles and four 4×4 squares, you have the right number of faces, but they must match the specific dimensions of a valid cuboid.
For a cuboid with dimensions , you need three pairs of identical opposite faces. Check if your given faces can form these three pairs with consistent edge lengths.
An orthohedron is just another name for a rectangular prism or cuboid. 'Not possible' means these specific faces cannot be arranged to form a valid 3D rectangular shape.
No! A cuboid must use exactly 6 faces - no more, no less. If your given faces can't form exactly 6 faces of a cuboid, then it's impossible.
Multiply each face's area by how many times it appears:
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