An orthohedron has the dimensions: 4, 7, 10.
How many rectangles is it formed of and what are their dimensions?
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An orthohedron has the dimensions: 4, 7, 10.
How many rectangles is it formed of and what are their dimensions?
To solve this problem, we'll follow these steps:
Now, let's work through each step:
Step 1: The orthohedron's dimensions are given as , , and .
Step 2: A cuboid (orthohedron) has three pairs of opposite rectangular faces:
- Pair 1: Two rectangles with dimensions .
- Pair 2: Two rectangles with dimensions .
- Pair 3: Two rectangles with dimensions .
Step 3: Count each of the pairs to verify the total number of rectangles formed.
We find there are 6 rectangles in total, with the dimensions specified above fulfilling the conditions for each face of the cuboid.
The solution to the problem is that the orthohedron is formed of:
2 Rectangles ,
2 Rectangles ,
2 Rectangles .
These dimensions and quantities match choice #3 in the answer options provided.
2 Rectangles 4X7
2 Rectangles 4X10
2 Rectangles 7X10
A cuboid is shown below:
What is the surface area of the cuboid?
A cuboid has 6 faces total - think of a box! Each face is rectangular, and opposite faces are identical. So you get 3 pairs of matching rectangles.
Take the 3 dimensions two at a time: 4×7, 4×10, and 7×10. Each pair forms the dimensions of one type of rectangular face, and you get 2 of each type.
They're the same thing! An orthohedron is just the fancy mathematical name for a rectangular prism or cuboid - a 3D shape with rectangular faces and right angles.
No! You just need to count the pairs correctly. It doesn't matter if you call them front/back, left/right, or top/bottom - just make sure you have all three different rectangle sizes.
If dimensions were like 4×4×10, you'd have squares instead of rectangles for some faces! The problem would ask about squares and rectangles separately in that case.
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