Surface Area Calculation: Effect of Tripling Width on Rectangular Prism

Surface Area Changes with Dimension Scaling

How will the surface area of a certain rectangular prism change if we triple the width?

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 How will the surface area of the box change if we triple the width?
00:03 Let's use the formula for calculating the surface area of a box
00:14 Let's substitute 3W instead of W according to the given data
00:33 Let's break down all the products of 3W to 1 and 2
01:01 Let's arrange the parentheses in a convenient way
01:18 Let's divide the parentheses into the original formula plus the difference
01:31 Let's identify the original formula for the surface area of a box
01:43 Let's factor out common terms from the parentheses
01:56 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

How will the surface area of a certain rectangular prism change if we triple the width?

2

Step-by-step solution

To solve this problem, let's follow these steps:

  • Step 1: Calculate the original surface area of the prism.
  • Step 2: Calculate the surface area after tripling the width.
  • Step 3: Determine the change in surface area.

First, the original surface area of the rectangular prism is given by the formula:
SA=2(lw+lh+wh) SA = 2(lw + lh + wh) .

Step 1: Substitute the original dimensions:
SAoriginal=2(lw+lh+wh) SA_{\text{original}} = 2(lw + lh + wh) .

Step 2: Now, when we triple the width, the new width is 3w 3w . Substitute 3w 3w into the surface area formula:
SAnew=2(l(3w)+lh+(3w)h) SA_{\text{new}} = 2(l(3w) + lh + (3w)h) .
This simplifies to:
SAnew=2(3lw+lh+3wh)=6lw+2lh+6wh SA_{\text{new}} = 2(3lw + lh + 3wh) = 6lw + 2lh + 6wh .

Step 3: Subtract the original surface area from the new one to find the change:
ΔSA=SAnewSAoriginal=(6lw+2lh+6wh)(2lw+2lh+2wh) \Delta SA = SA_{\text{new}} - SA_{\text{original}} = (6lw + 2lh + 6wh) - (2lw + 2lh + 2wh) .
Thus, ΔSA=4lw+4wh \Delta SA = 4lw + 4wh .

This change can be factorized further as:
ΔSA=4(l(w+h)) \Delta SA = 4(l(w + h)) .

Therefore, the surface area will increase by 4(w+h)l 4(w + h)l .

Thus, the correct answer is: It will increase by (w+h)l4 (w + h) \cdot l \cdot 4 . This is choice 3 and 4.

3

Final Answer

It will increase by (Width+Height)Lengh4 (Width+Height)\cdot Lengh\cdot4

Key Points to Remember

Essential concepts to master this topic
  • Formula: Surface area equals 2(lw + lh + wh) for rectangular prisms
  • Technique: Replace w with 3w: 2(l(3w) + lh + (3w)h) = 6lw + 2lh + 6wh
  • Check: Change = New SA - Original SA = 4lw + 4wh = 4(w + h)l ✓

Common Mistakes

Avoid these frequent errors
  • Thinking surface area triples when width triples
    Don't assume the surface area simply triples when one dimension triples = wrong answer! Only some faces involve width, not all six faces. Always calculate the new surface area using the formula, then find the difference.

Practice Quiz

Test your knowledge with interactive questions

A cuboid is shown below:

222333555

What is the surface area of the cuboid?

FAQ

Everything you need to know about this question

Why doesn't the surface area just triple when I triple the width?

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Because a rectangular prism has 6 faces, and only 4 of them involve the width! The top and bottom faces (lw) and the two side faces (wh) change, but the front and back faces (lh) stay the same.

How do I remember the surface area formula?

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Think of it as 2 times the sum of all three face areas: 2(lw + lh + wh). Each type of face appears twice on opposite sides of the prism.

What if I triple the length instead of width?

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Use the same method! Replace l with 3l in the formula. The increase would be 4l(w + h) instead of 4w(l + h).

Can I use this method for other dimension changes?

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Absolutely! Whether you double, triple, or multiply by any factor, substitute the new dimension into SA=2(lw+lh+wh) SA = 2(lw + lh + wh) and find the difference.

Why is the answer written as 4(w + h)l instead of 4lw + 4wh?

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Both forms are correct! Factoring 4lw + 4wh = 4w(l + h) makes it easier to see the pattern and match the answer choices given in the problem.

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