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To solve this problem, we'll follow these steps:
Now, let's work through each step:
Step 1: To find the square root of 64, we seek a number that, when multiplied by itself, equals 64.
Step 2: Consider the sequence of perfect squares: , , , , , , , .
Step 3: We see that . Therefore, the square root of 64 is 8.
Therefore, the solution to this problem is .
8
\( \sqrt{100}= \)
A square root is a number that when multiplied by itself gives you the original number. So asks: "What number times itself equals 64?"
Start with the basics: , , , , . Practice these daily and gradually work up to !
When we write , we want the positive square root, which is 8. While both 8 and -8 multiply to give 64, the square root symbol always means the positive answer.
If it's not a perfect square (like ), you can estimate between known perfect squares or use a calculator. Since and , is slightly more than 7.
Verification catches calculation errors! Simply multiply your answer by itself: . If it matches the original number under the square root, you're correct!
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