Calculate the Volume: Cuboid with Dimensions 4×2×5 Containing Equal Parts

Question

Shown below is a cuboid containing 5 smaller cuboids of equal size.

AB = 4

BE = 2

EK = 5

Calculate the volume of the large cuboid.

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Video Solution

Solution Steps

00:00 Calculate the volume of the large box
00:03 We'll use the formula for calculating box volume
00:07 width times height times length
00:12 We'll substitute appropriate values and solve for the volume
00:23 This is the volume of the small box
00:26 The volume of the large box equals 5 times the volume of the small box
00:37 We'll substitute the value of the small box volume and solve for the volume
00:40 And this is the solution to the question

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Calculate the volume of one smaller cuboid.
  • Step 2: Multiply the volume of one smaller cuboid by the number of cuboids (5) to find the total volume of the large cuboid.

Now, let's work through each step:
Step 1: The dimensions for each smaller cuboid are given as:

  • Length: 4cm 4 \, \text{cm}
  • Width: 2cm 2 \, \text{cm}
  • Height: 5cm 5 \, \text{cm}
Using the volume formula for a cuboid, we find the volume of one smaller cuboid:
Vsmall=4×2×5=40cm3 V_{\text{small}} = 4 \times 2 \times 5 = 40 \, \text{cm}^3
Step 2: Since there are 5 such smaller cuboids, the total volume for the large cuboid is:
Vlarge=5×40=200cm3 V_{\text{large}} = 5 \times 40 = 200 \, \text{cm}^3

Therefore, the volume of the large cuboid is 200cm3 200 \, \text{cm}^3 .

Answer

200 cm³