Calculate Triangle Perimeter: Right Triangle with Sides 7 and 3

A triangle has three sides, not two! You need to find the missing hypotenuse using the Pythagorean Theorem first. The perimeter is the sum of all three sides.

No! $\sqrt{58}$ is already in its simplest form since 58 = 2 × 29, and neither 2 nor 29 are perfect squares. Leave it as $10 + \sqrt{58}$.

The hypotenuse is always the longest side and sits opposite the right angle (90°). In this triangle, it's the diagonal side connecting vertices A and C.

You could calculate $\sqrt{58} ≈ 7.62$, but the exact answer $10 + \sqrt{58}$ is preferred in mathematics unless specifically asked for a decimal approximation.

It doesn't matter! Both 7 and 3 are legs of the right triangle, so $7^2 + 3^2$ gives the same result as $3^2 + 7^2$. The hypotenuse is still $\sqrt{58}$.