Calculate Water Height Y in a 150 cm³ Rectangular Prism with 50 ml Liquid

Question

50 ml of liquid is poured into a rectangular prism with a volume of 150 cm.

The distance between the water line and the top of the rectangular prism is 3 cm.

What is the value of Y, which represents the height of the water?

Video Solution

Solution Steps

00:00 Find the water level height Y
00:03 We want to find the volume of the empty box
00:07 Subtract the water volume from the total box volume
00:11 This is the volume of the empty box
00:19 We'll use the formula for calculating box volume
00:22 Width multiplied by height multiplied by length
00:26 We'll substitute appropriate values according to the given data and solve for X
00:33 Isolate X
00:42 This is the box width X
00:49 We'll calculate the liquid volume and find the water level height Y
00:55 We'll use the formula for calculating box volume
00:59 We'll substitute appropriate values according to the given data and solve for Y
01:07 Isolate Y
01:13 And this is the solution to the problem

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Calculate the base area of the rectangular prism.
  • Step 2: Use the base area to find the height of the water, Y Y .

Now, let's work through each step:

Step 1: The volume of the rectangular prism is given as 150 cm3^3. Let's denote the height of the prism without any liquid as H H , and the gap from the water line to the top of the prism is 3 cm. Thus, the total height is H3 H - 3 . The water volume given is 50 cm3^3, which means the volume occupied by the air is:

15050=100 150 - 50 = 100 cm3^3.

Since the gap is 3 cm (the height of air column), the base area A A can be calculated as:

A×3=100 A \times 3 = 100 .

This implies A=100333.3 A = \frac{100}{3} \approx 33.\overline{3} cm2^2.

Step 2: Now, to find Y Y (the height of water):

We use the formula for the volume of water in the prism:

A×Y=50 A \times Y = 50 ,

where A=33.3 A = 33.\overline{3} cm2^2. Therefore,

Y=5033.3=1.5 Y = \frac{50}{33.\overline{3}} = 1.5 cm.

Therefore, the solution to the problem is Y=1.5cm Y = 1.5 \, \text{cm} .

Answer

1.5 cm