Fill in the Blanks: Solve \((?\times x+?)^2=16x^2+32x+16\) with Completion

Perfect Square Trinomials with Coefficient Matching

Fill in the blanks:

(?×x+?)2=16x2+32x+16 (?\times x+?)^2=16x^2+32x+16

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Complete the missing
00:10 Let's break down 16 into its square root
00:26 Let's break down 32 into factors 2, 4, and 4
00:49 Let's use the shortened multiplication formulas to find the brackets
00:56 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Fill in the blanks:

(?×x+?)2=16x2+32x+16 (?\times x+?)^2=16x^2+32x+16

2

Step-by-step solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify how to match the quadratic expression with the binomial square.
  • Step 2: Compare coefficients for alignment and solve for the unknowns.
  • Step 3: Verify by reconstructing the square from known coefficients.

Now, let's work through each step:

Step 1: The given expression is (?×x+?)2=16x2+32x+16(?\times x+?)^2 = 16x^2 + 32x + 16. The goal is to match this with (ax+b)2=a2x2+2abx+b2(ax + b)^2 = a^2x^2 + 2abx + b^2.

Step 2: Compare the expanded form with the expanded square:

  • Match a2x2a^2x^2 with 16x216x^2: a2=16a^2 = 16. Solving gives a=4a = 4.
  • Match 2abx2abx with 32x32x: 2ab=322ab = 32. Substituting a=4a = 4, we get 2×4×b=322 \times 4 \times b = 32 b=4\Rightarrow b = 4.
  • Match b2b^2 with 1616: b2=16b^2 = 16. We already confirmed b=4b = 4.

Step 3: Since both aa and bb values match consistently through all comparisons, reconstruct the expression:

(4x+4)2=(4)2x2+2(4)(4)x+(4)2=16x2+32x+16(4x + 4)^2 = (4)^2x^2 + 2(4)(4)x + (4)^2 = 16x^2 + 32x + 16.

This confirms the correct filling of blanks with consistent polynomial expression alignment.

Therefore, the filled-in expression is (4×x+4)2(4 \times x + 4)^2, matching with the correct choice.

Therefore, the correct solution is (4,4)(4, 4).

3

Final Answer

4, 4 4,\text{ }4

Key Points to Remember

Essential concepts to master this topic
  • Pattern Recognition: Perfect square trinomials follow (ax+b)2=a2x2+2abx+b2(ax + b)^2 = a^2x^2 + 2abx + b^2 form
  • Coefficient Matching: Compare systematically: a2=16a^2 = 16 gives a=4a = 4, then 2ab=322ab = 32 gives b=4b = 4
  • Verification: Expand your answer: (4x+4)2=16x2+32x+16(4x + 4)^2 = 16x^2 + 32x + 16

Common Mistakes

Avoid these frequent errors
  • Guessing coefficients without systematic comparison
    Don't just try random numbers like (2x + 8)² or (8x + 2)² = wrong expansions! This wastes time and leads to incorrect answers. Always match coefficients systematically: first find a from the x² term, then use it to find b from the middle term.

Practice Quiz

Test your knowledge with interactive questions

Choose the expression that has the same value as the following:


\( (x+3)^2 \)

FAQ

Everything you need to know about this question

How do I know this is a perfect square trinomial?

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Look for the pattern! A perfect square trinomial has three terms where the first and last terms are perfect squares, and the middle term equals twice the product of the square roots of the outer terms.

What if I get two possible values when taking square roots?

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When solving a2=16a^2 = 16, you get a=±4a = ±4. Check which sign works by testing the middle term. Here, 2(4)(b)=322(4)(b) = 32 confirms we need positive 4.

Why do I need to check all three terms?

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Consistency is key! All three coefficient equations must give the same values for a and b. If they don't match, you've made an error or the expression isn't a perfect square.

Can I work backwards from the constant term first?

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You could start with b2=16b^2 = 16 to get b=±4b = ±4, but it's usually easier to start with the coefficient of x² since it directly gives you the first blank.

What if the numbers don't work out to be integers?

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Perfect square trinomials in fill-in-the-blank problems typically have integer coefficients. If you're getting fractions or decimals, double-check your arithmetic or reconsider the problem setup.

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