Given the expression of the quadratic function
The symmetrical axis of the expression must be found.
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Given the expression of the quadratic function
The symmetrical axis of the expression must be found.
To find the axis of symmetry for the quadratic function , we employ the formula for the axis of symmetry of a parabola given by , which is .
Given , we identify the coefficients from the function:
Substituting these values into the formula:
Thus, the axis of symmetry for the quadratic function is .
Therefore, the solution to the problem is .
Given the expression of the quadratic function
Finding the symmetry point of the function
\( f(x)=-5x^2+10 \)
When there's no x term (like in ), it means the coefficient b = 0. This creates a perfect vertical symmetry around the y-axis!
Because b = 0 in our function! Using the formula . When b = 0, the parabola is perfectly centered on the y-axis.
Test equal distances from the axis! Pick any value like x = 2: . Then try x = -2: . Same result means correct axis!
You'd get the wrong formula setup! Always identify coefficients from standard form . Here: a = 4 (coefficient of ), b = 0, c = 6 (constant term).
No! The constant c only moves the parabola up or down. The axis of symmetry depends only on coefficients a and b in the formula .
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