Finding the Axis of Symmetry: Solve for Symmetry in f(x) = 4x^2 + 6

Axis of Symmetry with Zero Linear Term

Given the expression of the quadratic function

The symmetrical axis of the expression must be found.

f(x)=4x2+6 f(x)=4x^2+6

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find the axis of symmetry for the function
00:03 The axis of symmetry is the X value at the vertex point
00:06 The point where if you fold the parabola in half, both halves are identical
00:10 Let's examine the function coefficients
00:16 We'll use the formula to calculate the vertex point
00:22 We'll substitute appropriate values according to the given data and solve for X at the point
00:29 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Given the expression of the quadratic function

The symmetrical axis of the expression must be found.

f(x)=4x2+6 f(x)=4x^2+6

2

Step-by-step solution

To find the axis of symmetry for the quadratic function f(x)=4x2+6 f(x) = 4x^2 + 6 , we employ the formula for the axis of symmetry of a parabola given by ax2+bx+c ax^2 + bx + c , which is x=b2a x = -\frac{b}{2a} .

Given f(x)=4x2+0x+6 f(x) = 4x^2 + 0x + 6 , we identify the coefficients from the function:

  • a=4 a = 4
  • b=0 b = 0

Substituting these values into the formula:

x=b2a=02×4=0 x = -\frac{b}{2a} = -\frac{0}{2 \times 4} = 0

Thus, the axis of symmetry for the quadratic function is x=0 x = 0 .

Therefore, the solution to the problem is x=0\mathbf{x = 0}.

3

Final Answer

x=0 x=0

Key Points to Remember

Essential concepts to master this topic
  • Formula: Use x=b2a x = -\frac{b}{2a} for standard form quadratics
  • Technique: When b = 0, axis becomes x=02a=0 x = -\frac{0}{2a} = 0
  • Check: Verify by testing equal distances: f(-1) = 10, f(1) = 10 ✓

Common Mistakes

Avoid these frequent errors
  • Forgetting the linear coefficient is zero
    Don't look for a visible x term when it's missing = using wrong values for b! When no x term appears, b = 0, not undefined. Always identify b = 0 in functions like 4x2+6 4x^2 + 6 and apply the formula correctly.

Practice Quiz

Test your knowledge with interactive questions

Given the expression of the quadratic function

Finding the symmetry point of the function

\( f(x)=-5x^2+10 \)

FAQ

Everything you need to know about this question

What does it mean when there's no x term in the middle?

+

When there's no x term (like in f(x)=4x2+6 f(x) = 4x^2 + 6 ), it means the coefficient b = 0. This creates a perfect vertical symmetry around the y-axis!

Why is the axis of symmetry x = 0 and not something else?

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Because b = 0 in our function! Using the formula x=b2a=02(4)=0 x = -\frac{b}{2a} = -\frac{0}{2(4)} = 0 . When b = 0, the parabola is perfectly centered on the y-axis.

How can I double-check that x = 0 is correct?

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Test equal distances from the axis! Pick any value like x = 2: f(2)=4(2)2+6=22 f(2) = 4(2)^2 + 6 = 22 . Then try x = -2: f(2)=4(2)2+6=22 f(-2) = 4(-2)^2 + 6 = 22 . Same result means correct axis!

What if I mistakenly used a = 6 instead of a = 4?

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You'd get the wrong formula setup! Always identify coefficients from standard form ax2+bx+c ax^2 + bx + c . Here: a = 4 (coefficient of x2 x^2 ), b = 0, c = 6 (constant term).

Does the constant term affect the axis of symmetry?

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No! The constant c only moves the parabola up or down. The axis of symmetry depends only on coefficients a and b in the formula x=b2a x = -\frac{b}{2a} .

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