Finding the Axis of Symmetry: Solve for Symmetry in f(x) = 4x^2 + 6

Axis of Symmetry with Zero Linear Term

Given the expression of the quadratic function

The symmetrical axis of the expression must be found.

f(x)=4x2+6 f(x)=4x^2+6

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:09 Let's find the axis of symmetry for this function.
00:13 Remember, the axis of symmetry is the X value at the ver tex.
00:18 Imagine folding the parabola in half, both sides will match perfect ly.
00:24 First, let's look at the function's coefficients.
00:28 We'll use a formula to find the vertex point.
00:33 Substitute the values we have and solve for X to get the vertex.
00:39 And there you go! That's the solution.

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Given the expression of the quadratic function

The symmetrical axis of the expression must be found.

f(x)=4x2+6 f(x)=4x^2+6

2

Step-by-step solution

To find the axis of symmetry for the quadratic function f(x)=4x2+6 f(x) = 4x^2 + 6 , we employ the formula for the axis of symmetry of a parabola given by ax2+bx+c ax^2 + bx + c , which is x=b2a x = -\frac{b}{2a} .

Given f(x)=4x2+0x+6 f(x) = 4x^2 + 0x + 6 , we identify the coefficients from the function:

  • a=4 a = 4
  • b=0 b = 0

Substituting these values into the formula:

x=b2a=02×4=0 x = -\frac{b}{2a} = -\frac{0}{2 \times 4} = 0

Thus, the axis of symmetry for the quadratic function is x=0 x = 0 .

Therefore, the solution to the problem is x=0\mathbf{x = 0}.

3

Final Answer

x=0 x=0

Key Points to Remember

Essential concepts to master this topic
  • Formula: Use x=b2a x = -\frac{b}{2a} for standard form quadratics
  • Technique: When b = 0, axis becomes x=02a=0 x = -\frac{0}{2a} = 0
  • Check: Verify by testing equal distances: f(-1) = 10, f(1) = 10 ✓

Common Mistakes

Avoid these frequent errors
  • Forgetting the linear coefficient is zero
    Don't look for a visible x term when it's missing = using wrong values for b! When no x term appears, b = 0, not undefined. Always identify b = 0 in functions like 4x2+6 4x^2 + 6 and apply the formula correctly.

Practice Quiz

Test your knowledge with interactive questions

Given the expression of the quadratic function

The symmetrical axis of the expression must be found.

\( f(x)=7x^2 \)

FAQ

Everything you need to know about this question

What does it mean when there's no x term in the middle?

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When there's no x term (like in f(x)=4x2+6 f(x) = 4x^2 + 6 ), it means the coefficient b = 0. This creates a perfect vertical symmetry around the y-axis!

Why is the axis of symmetry x = 0 and not something else?

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Because b = 0 in our function! Using the formula x=b2a=02(4)=0 x = -\frac{b}{2a} = -\frac{0}{2(4)} = 0 . When b = 0, the parabola is perfectly centered on the y-axis.

How can I double-check that x = 0 is correct?

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Test equal distances from the axis! Pick any value like x = 2: f(2)=4(2)2+6=22 f(2) = 4(2)^2 + 6 = 22 . Then try x = -2: f(2)=4(2)2+6=22 f(-2) = 4(-2)^2 + 6 = 22 . Same result means correct axis!

What if I mistakenly used a = 6 instead of a = 4?

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You'd get the wrong formula setup! Always identify coefficients from standard form ax2+bx+c ax^2 + bx + c . Here: a = 4 (coefficient of x2 x^2 ), b = 0, c = 6 (constant term).

Does the constant term affect the axis of symmetry?

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No! The constant c only moves the parabola up or down. The axis of symmetry depends only on coefficients a and b in the formula x=b2a x = -\frac{b}{2a} .

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