Finding the Axis of Symmetry in the Quadratic Equation f(x) = 3x^2 + 2

Question

A quadratic equation is graphed below.

What is the axis of symmetry for the graph f(x)=3x2+2 f(x)=3x^2+2 ?

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Video Solution

Solution Steps

00:00 Find the axis of symmetry for the function
00:03 The axis of symmetry is the X value at the vertex point
00:06 The point where if you fold the parabola in half, both halves are identical
00:10 Let's look at the function's coefficients
00:17 We'll use the formula to calculate the vertex point
00:21 We'll substitute appropriate values according to the given data and solve for X at the point
00:30 And this is the solution to the question

Step-by-Step Solution

To determine the axis of symmetry for the function f(x)=3x2+2 f(x) = 3x^2 + 2 , we follow these steps:

  • Identify the coefficients from the function. Here, a=3 a = 3 and b=0 b = 0 . The constant term c=2 c = 2 does not affect the axis of symmetry.
  • Use the axis of symmetry formula for a quadratic function: x=b2a x = -\frac{b}{2a} .
  • Substitute the values for b b and a a into the formula: x=02×3=0 x = -\frac{0}{2 \times 3} = 0 .

This calculation shows that the axis of symmetry for the graph of the quadratic function is x=0 x = 0 .

Thus, the solution to the problem is that the axis of symmetry is x=0 x = 0 .

Answer

x=0 x=0