Determine the Largest Value Among Given Numbers

Square Root Products with Exponent Laws

Determine which of the following options has the greatest numerical value:

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Select the largest value
00:03 When multiplying the root of a number (A) by the root of another number (B)
00:06 The result equals the root of their product (A times B)
00:09 Apply this formula to our exercise and proceed to calculate the products
00:12 We'll use this method for each expression in order to determine the largest one
00:25 This is the solution

Step-by-step written solution

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1

Understand the problem

Determine which of the following options has the greatest numerical value:

2

Step-by-step solution

In order to determine which of the suggested options has the largest numerical value, apply the three laws of exponents:

a. Definition of root as an exponent:

an=a1n \sqrt[n]{a}=a^{\frac{1}{n}} b. Law of exponents for an exponent applied to a product in parentheses (in reverse order):

anbn=(ab)n a^n\cdot b^n=(a\cdot b)^n c. Law of exponents for an exponent raised to an exponent:

(am)n=amn (a^m)^n=a^{m\cdot n}

Let's deal with each of the suggested options (in the answers), starting by converting the square root to exponent notation, using the law of exponents mentioned in a' earlier:

55512512222122123331231244412412 \sqrt{5}\cdot\sqrt{5} \rightarrow 5^{\frac{1}{2}}\cdot5^{\frac{1}{2}}\\ \sqrt{2}\cdot\sqrt{2} \rightarrow 2^{\frac{1}{2}}\cdot2^{\frac{1}{2}}\\ \sqrt{3}\cdot\sqrt{3} \rightarrow 3^{\frac{1}{2}}\cdot3^{\frac{1}{2}}\\ \sqrt{4}\cdot\sqrt{4} \rightarrow 4^{\frac{1}{2}}\cdot4^{\frac{1}{2}}\\ Due to the fact that both terms in the product have the same exponent, we are able to apply the law of exponents mentioned in b' earlier and then proceed to combine them together inside of the parentheses product, raised to the same exponent . Once completed we can then calculate the result of the product in the parentheses:

512512(55)12=(52)12212212(22)12=(22)12312312(33)12=(32)12412412(44)12=(42)12 5^{\frac{1}{2}}\cdot5^{\frac{1}{2}} \rightarrow (5\cdot5)^{\frac{1}{2}}=(5^2)^{\frac{1}{2}} \\ 2^{\frac{1}{2}}\cdot2^{\frac{1}{2}}\rightarrow(2\cdot2)^{\frac{1}{2}}=(2^2)^{\frac{1}{2}} \\ 3^{\frac{1}{2}}\cdot3^{\frac{1}{2}} \rightarrow (3\cdot3)^{\frac{1}{2}}=(3^2)^{\frac{1}{2}} \\ 4^{\frac{1}{2}}\cdot4^{\frac{1}{2}}\rightarrow(4\cdot4)^{\frac{1}{2}}=(4^2)^{\frac{1}{2}} \\ Proceed to apply the law of exponents mentioned in c' and then calculate the exponent inside of the parentheses:

(52)125212=51=5(22)122212=21=2(42)124212=41=4(32)123212=31=3 (5^2)^{\frac{1}{2}}\rightarrow 5^{2\cdot \frac{1}{2}}=5^1=5 \\ (2^2)^{\frac{1}{2}}\rightarrow 2^{2\cdot \frac{1}{2}}=2^1=2 \\ (4^2)^{\frac{1}{2}}\rightarrow 4^{2\cdot \frac{1}{2}}=4^1=4 \\ (3^2)^{\frac{1}{2}}\rightarrow 3^{2\cdot \frac{1}{2}}=3^1=3 \\

We have determined that the number in option a' is representative of the largest value:

5>4>3>2 5>4>3>2 The correct answer is a'.

3

Final Answer

55 \sqrt{5}\cdot\sqrt{5}

Key Points to Remember

Essential concepts to master this topic
  • Rule: Convert square roots to fractional exponents: a=a12 \sqrt{a} = a^{\frac{1}{2}}
  • Technique: Use nn=n12n12=n \sqrt{n} \cdot \sqrt{n} = n^{\frac{1}{2}} \cdot n^{\frac{1}{2}} = n
  • Check: Verify 55=5 \sqrt{5} \cdot \sqrt{5} = 5 is largest: 5 > 4 > 3 > 2 ✓

Common Mistakes

Avoid these frequent errors
  • Trying to estimate square root values instead of simplifying
    Don't approximate √5 ≈ 2.2, then multiply 2.2 × 2.2 = 4.84! This creates rounding errors and confusion. Always use the exponent law: √a · √a = a exactly.

Practice Quiz

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Choose the largest value

FAQ

Everything you need to know about this question

Why does √5 × √5 equal exactly 5?

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Because 5 \sqrt{5} means "the number that when multiplied by itself gives 5." So 5×5=5 \sqrt{5} \times \sqrt{5} = 5 by definition!

Do I need to memorize all the exponent laws?

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Focus on the key pattern: aa=a \sqrt{a} \cdot \sqrt{a} = a . This works because square root undoes squaring, so the roots cancel out and leave the original number.

What if the question had different roots like ∛8?

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Same principle! 838383=8 \sqrt[3]{8} \cdot \sqrt[3]{8} \cdot \sqrt[3]{8} = 8 . The number of identical roots must match the index of the radical.

Can I use a calculator for this type of problem?

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You could, but it's faster to recognize the pattern! nn=n \sqrt{n} \cdot \sqrt{n} = n always, so just compare the numbers under the radicals: 2, 3, 4, and 5.

How do I remember which exponent laws to use?

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  • Same base, multiply exponents: aman=am+n a^m \cdot a^n = a^{m+n}
  • Power of power: (am)n=amn (a^m)^n = a^{mn}
  • For this problem, both give the same result!

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