Multiply Square Roots: √5 × √2 × √5 × √2 Simplification

Square Root Multiplication with Repeated Factors

Solve the following exercise:

5252= \sqrt{5}\cdot\sqrt{2}\cdot\sqrt{5}\cdot\sqrt{2}=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Simplify the following problem
00:03 When multiplying the root of a number (A) by the root of another number (B)
00:06 The result equals the root of their product (A times B)
00:10 Apply this formula to our exercise and calculate the products
00:16 Calculate each product separately
00:19 A number multiplied by itself is actually squared
00:22 A root cancels out a square, and that's the solution

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve the following exercise:

5252= \sqrt{5}\cdot\sqrt{2}\cdot\sqrt{5}\cdot\sqrt{2}=

2

Step-by-step solution

In order to simplify the given expression, apply two laws of exponents:

a. Root definition as an exponent:

an=a1n \sqrt[n]{a}=a^{\frac{1}{n}}

b. The law of exponents for exponents applied to multiplication of terms in parentheses (in reverse direction):

xnyn=(xy)n x^n\cdot y^n =(x\cdot y)^n

Begin by converting the square roots to exponents using the law of exponents mentioned in a:

5252=512212512212= \sqrt{5}\cdot\sqrt{2}\cdot\sqrt{5}\cdot\sqrt{2}= \\ \downarrow\\ 5^{\frac{1}{2}}\cdot2^{\frac{1}{2}}\cdot5^{\frac{1}{2}}\cdot2^{\frac{1}{2}}=

Due to the fact that there is a multiplication operation between four terms with identical exponents, we are able to apply the law of exponents mentioned in b (which also applies to multiplication of multiple terms in parentheses) Combine them together in a multiplication operation within parentheses that are raised to the same exponent:

512212512212=(5252)12=10012=100=10 5^{\frac{1}{2}}\cdot2^{\frac{1}{2}}\cdot5^{\frac{1}{2}}\cdot2^{\frac{1}{2}}= \\ (5\cdot2\cdot5\cdot2)^{\frac{1}{2}}=\\ 100^{\frac{1}{2}}=\\ \sqrt{100}=\\ \boxed{10}

In the final steps, we first performed the multiplication within the parentheses, we then once again used the root definition as an exponent mentioned in a (in reverse direction) to return to root notation, and in the final stage, we calculated the known square root of 100.

Therefore, we can identify that the correct answer is answer d.

3

Final Answer

10 10

Key Points to Remember

Essential concepts to master this topic
  • Rule: Convert square roots to fractional exponents for easier manipulation
  • Technique: Group identical terms: 55=5 \sqrt{5} \cdot \sqrt{5} = 5 and 22=2 \sqrt{2} \cdot \sqrt{2} = 2
  • Check: Verify 5×2=10 5 \times 2 = 10 gives same result as original expression ✓

Common Mistakes

Avoid these frequent errors
  • Adding instead of multiplying square root terms
    Don't add 5+2+5+2=25+22 \sqrt{5} + \sqrt{2} + \sqrt{5} + \sqrt{2} = 2\sqrt{5} + 2\sqrt{2} ! Square roots multiply, they don't add when there's a multiplication sign between them. Always multiply: 5252=(5)2(2)2=5×2=10 \sqrt{5} \cdot \sqrt{2} \cdot \sqrt{5} \cdot \sqrt{2} = (\sqrt{5})^2 \cdot (\sqrt{2})^2 = 5 \times 2 = 10 .

Practice Quiz

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FAQ

Everything you need to know about this question

Why can I multiply square roots like regular numbers?

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Square roots follow the same multiplication rules as regular numbers! When you see ab \sqrt{a} \cdot \sqrt{b} , it equals ab \sqrt{a \cdot b} . This property makes calculations much easier.

What happens when I multiply the same square root twice?

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When you multiply nn \sqrt{n} \cdot \sqrt{n} , you get n! This is because (n)2=n (\sqrt{n})^2 = n . So 55=5 \sqrt{5} \cdot \sqrt{5} = 5 .

Can I simplify this without converting to exponents?

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Yes! You can group the identical terms directly: 5252=(55)(22)=52=10 \sqrt{5} \cdot \sqrt{2} \cdot \sqrt{5} \cdot \sqrt{2} = (\sqrt{5} \cdot \sqrt{5}) \cdot (\sqrt{2} \cdot \sqrt{2}) = 5 \cdot 2 = 10 .

Why is the answer 10 and not √100?

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Both are correct! 100=10 \sqrt{100} = 10 because 10 × 10 = 100. When you can simplify a square root to a whole number, always do it for the clearest answer.

What if the numbers under the square roots were different?

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If all four square roots were different, you'd multiply all the numbers under one square root sign: abcd=abcd \sqrt{a} \cdot \sqrt{b} \cdot \sqrt{c} \cdot \sqrt{d} = \sqrt{a \cdot b \cdot c \cdot d} .

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