Find Coefficients in the Linear Equation y=6-3x: Step-by-Step

To solve this problem, we need to match the parameters of the given equation $y = 6 - 3x$ with the standard quadratic form $y = ax^2 + bx + c$.

Here are the steps we will follow:

• Step 1: Identify the coefficients in the given equation.
• Step 2: Compare these coefficients with the standard form $y = ax^2 + bx + c$.
• Step 3: Determine the values of $a$, $b$, and $c$.

Let's apply these steps:

Step 1: The given equation is $y = 6 - 3x$. Notice that there is no $x^2$ term. We can write it in a form closer to the quadratic standard by expressing it as:

$y = 0x^2 - 3x + 6$

Step 2: Compare this with the quadratic form $y = ax^2 + bx + c$:

• The coefficient of $x^2$ is 0, so $a = 0$.
• The coefficient of $x$ is -3, so $b = -3$.
• The constant term is 6, so $c = 6$.

Therefore, the parameters for the quadratic form are $a = 0$, $b = -3$, and $c = 6$.

Finally, when we check the answer choices provided, we find that choice 1 matches our derived coefficients.

The correct choice is: $a = 0, b = -3, c = 6$.