Find Coefficients in y = 4x + 4x²: Term-by-Term Analysis

Question

Identify the coefficients based on the following equation

y=4x+4x2 y=4x+4x^2

Video Solution

Solution Steps

00:00 Find the function coefficients
00:03 We'll use the formula to represent a quadratic equation
00:12 We'll arrange the equation to match the formula
00:35 We'll separate the variable from the coefficient
00:44 We'll compare the formula to our equation and find the coefficients
00:55 And this is the solution to the question

Step-by-Step Solution

To solve this problem, let's follow these steps:

  • Step 1: Understand the given function.
  • Step 2: Compare it with the standard quadratic form.
  • Step 3: Identify the coefficients a a , b b , and c c .

Now, let's work through each step:

Step 1: We are given the function y=4x+4x2 y = 4x + 4x^2 , which is written in terms of x x .

Step 2: The standard form for a quadratic function is y=ax2+bx+c y = ax^2 + bx + c .

Step 3: We need to rearrange the given function and align it with the standard form for easy comparison:
y=4x2+4x+0 y = 4x^2 + 4x + 0 .

By comparing with y=ax2+bx+c y = ax^2 + bx + c , we can directly match the coefficients:
- The coefficient a a for x2 x^2 is 4 4 .
- The coefficient b b for x x is 4 4 .
- The constant term c c is 0 0 .

Therefore, the parameters are a=4,b=4,c=0 a = 4, b = 4, c = 0 .

Answer

a=4,b=4,c=0 a=4,b=4,c=0